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2 years ago

WILL MARK BRAINIEST

Mathematics

2 answers:

fenix001 [56]2 years ago

7 0

Answer:

A quadratic function in standard form is converted to vertex form by completing the square. The first two terms are used to create a perfect square trinomial after a zero pair is added. The zero pair is found by taking half of the x-term coefficient and squaring it. The original constant term and the negative value of the zero pair are then combined.

Step-by-step explanation:

PIT_PIT [208]2 years ago

4 0

Answer:

Read this,it should help!

The standard form of a quadratic function is y = ax 2 + bx + c. where a, b and c are real numbers, and a ≠ 0. Using Vertex Form to Derive Standard Form. Write the vertex form of a quadratic function. y = a(x - h) 2 + k. Square the binomial. y = a(x 2 - 2xh + h 2) + k. y = ax 2 - 2ahx + ah 2 + k

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Answer:

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Step-by-step explanation:

A(x) = 4x ( x + 10 ) - 2x ( 8 ) + $\frac{2x(x)}{2}$ + $\frac{2x(x+2)}{2}$

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2 years ago

Simplify the expression. 6/7x - 8 - 4/7x - 8

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The answer to this is - 2(56x-1)/ 7x

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2 years ago

The sum of the components of anything equals the whole thing. Which property/postulate does this statement represent?

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The property that is being described in the statement "The sum of the components of anything equals the whole thing" would be the Partition Postulate. It is simply the whole is equal to the sum of its parts. For instance we have a line where it contains points W, X, Y and Z, then WX + XY + YZ = WZ.

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2 years ago

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

$\mu_s=np=500*0.90=450$

The standard deviation will be:

$\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7$

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

$z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932$

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

$\mu=np=300*0.932=279.6$

The standard deviation will be:

$\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36$

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

$P(270\leq x\leq280)=P(269.5$

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

$P(X=280)=P(279.5$

8 0

2 years ago