Perfect squares follow this pattern:
So, two terms must be perfect squares of two certain roots. If so, the remaining term must be twice their product. Let's analyse the trinomials one by one:
1) x^2 is the square of x. -64 is not a perfect square. So, the trinomial is not a perfect square.
2) 4x^2 is the square of 2x. 9 is the square of 3. The remaining term, 12x, is indeed twice their product. So, we have
3) x^2 is the square of x. 100 is the square of 10. The remaining term, 20x, is indeed twice their product. So, we have
4) x^2 is the square of x. 16 is the square of 4. The remaining term, 4x, is not twice their product (it's only the product of 4 and x, so it should be doubled). So, this trinomial is not a perfect square.
True if by confidence you mean the margin of It being correct,If not Its false
She remove (withdrew) $55 from her account. Her saving balance(d) decreased by $55
Answer:
57
Step-by-step explanation:
It is given in the question that length CDA = 57.
Since the shape is a parallelogram, then we know that length AD=BC and AB=CD.
CDA = CD + AD
BCD = BC + CD
Since BC=AD and CD=CD
BCD = BC + CD is the same as CD + AD = CDA
Therefore BCD is the same length as CDA = 57
In other words, CDA is made up of a long side and a short side = 57
BCD is also made up of a long side and a short side, and since the longs sides are equal to each other and the short sides are also equal to each other in a parallelogram, BCD is the same length as CDA = 57.
Hope this helped!