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Aneli [31]
4 years ago
8

Describe the locations of 3 and -3 with respect to 0 on a number line.

Mathematics
1 answer:
Elina [12.6K]4 years ago
4 0
The answer is D, 3 is to the right and -3 is to the left
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Which is the graph of f(x) = x2 – 2x + 3?
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To find the graph of f(x) = x^2 - 2x + 3, you can either plug in values into where the x variable stands and solve for their corresponding y-values or you can also use your graphing calculator or even Desmos works! 

3 0
3 years ago
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Need help asap!!!!!!​
Mrac [35]

Answer: x=4

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What is tan 11 pie/6
tia_tia [17]

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5.75

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5 0
3 years ago
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

6 0
3 years ago
Jasmine sells bracelets at a local jewelry store in South Dekalb Mall. She has 1,190 purple beads and 2,125 pink beads. Each bra
jeka57 [31]

Answer:

39

Step-by-step explanation:

1190 + 2125 = 3315 (number of beads)

3315/85 = 36 (number of bracelets jasmine can make)

8 0
3 years ago
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