Answer:
2
Step-by-step explanation:
Simplify. Remember to follow PEMDAS and the left-> right rule.
In this case, multiply the whole number (6/1) with the numerator (1)
6 x 1 = 6
Next, simplify by dividing 6 with 3:
6/3 = 2
2 is your answer.
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When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.
The first factor is x - (a + √b).
The second factor is x - (a - √b).
The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
= x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
= x² - 2ax + x√b - x√b + a² - b
= x² - 2ax + a² - b
This is a quadratic polynomial, as expected.
If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
= a +/- (1/2)*√(4b)
= a +/- √b
x = a + √b, or x = a - √b, as expected.
Answer:
3 x 4 = 12, 12 divided by 2 ) x 1/2) = 6, 6 x 2 = 12(area of two triangles)
8 x 4 = 32
8 x 3 = 24
8 x 5 = 40
Let's add all the given areas:
12 + 32 + 24 + 40 = 108 m^2 is your answer.
Answer:
here's the solution ; -
=》
=》
=》
=》
so, required zeroes are : -3 and -5
