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zloy xaker [14]
3 years ago
9

PLEASE HELP Which table shows a proportional relationship

Mathematics
1 answer:
vfiekz [6]3 years ago
3 0

Answer:

The x y table or third table



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A student raises her grade average from a 75 to a 90. What was the percent of increase
son4ous [18]
This can be solved algebraically. Before we start, as context, to find a percentage you multiply by the percentage/100.

75*x=90 \\ x= \frac{90}{75}  \\  \\ \boxed{x=1.2}

This tells us that 90 is 120% of 75. However, your question wants us to find the <em>increase</em>, therefore we don't need that 100.
Therefore, the increase is 20%.
4 0
4 years ago
Solve 5x - (2x + 2) = x + (3x + 5) (make sure to type the number only)
Anit [1.1K]

Answer:

7

Step-by-step explanation:

To solve this problem we need to find x

First we need to do parenthesis

This means that the equation becomes 5x - 2x - 2 = x + 3x + 5

Next add or subtract, this simplifies it to 3x - 2= 4x + 5

After this bring the numbers on the right and the variables on the left

This means subtracting 4 on each side and adding 2 on each side

Now the equation becomes -x = 7

Lastly, put the negative on the right

x = 7

7 0
3 years ago
On a coordinate graph, which of the following is TRUE of Quadrant 3? is it A. The x and y values are both positive. B. The x val
Flura [38]
D is the answer . -JZ
6 0
3 years ago
Which of the following is the value of a when the function f(x) = 3|x| is written in the standard form of an absolute value
Gnoma [55]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Modulus functions.

Since here, the value of h and k are zero,hence

the value of the function f(x) = 3|x| is 3

====> answer is 3

4 0
3 years ago
Please help me with these factoring problems. Please help me solve. I can't do these!!
aleksley [76]
Simple...

you have: 

1.) -8x-16  --->>>

Factor out a -8 -->>

-8(x+2)

2.)9d+15db --->

Factor out 3d -->

3d(3+5b)

3.) 2a-9ax-->>

Factor out -a -->

-1a(9x-2)

Thus, your answer.
3 0
3 years ago
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