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Thepotemich [5.8K]
3 years ago
8

Tommy wished he practiced more before his violin concert. If he had practiced 1 1/2 more hours one week, he would have averaged

8 hours per week for the four week prior to his concert. How many hours did he practice in the 4 weeks?
Mathematics
1 answer:
Nimfa-mama [501]3 years ago
8 0

Answer:

30.5 hours

Step-by-step explanation:

If he were to average 8 hours PER week for 4 weeks, his total sum would have been:

8 * 4 = 32 hours

But he fell short of it. By how much?

By 1\frac{1}{2} hours!

So, he practiced 1  1/2 hours LESS THAN 32 hours, so his practice time is:

32-1\frac{1}{2}\\=32-1.5\\=30.5\\=30\frac{1}{2}

So, <u>he practiced 30.5 hours in the 4 weeks</u>

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The quarterback of a football team releases a pass at a height of 6 feet above the playing field, and the football is caught by
motikmotik

Answer:

t = 25.1seconds

Step-by-step explanation:

X(t)= 16cos75°t

Y(t)= 6 + (Vosin75°t - 16t^2)

Converting 78 yards to feet :

1 yard = 3 feet

78feet =?

78×3=234 feet

Y(t)= number of feet above the ground at t seconds

VoCos75° t = 234

t = 234/(VoCos75°)

At this time,4 = y(234/VoCos75°)

4 = 6 + VoSin75°(234/VoCos75) - 16(234/VoCos75°)^2

Vo= 140.66ft/s

Time,t= 234/(140.66× Cos75°)

t = 25.087seconds

t= 25.1 seconds (1 decimal place)

8 0
3 years ago
On her math test, Anna got I 32 questions out of 36 | questions correct. About | what percent of the questions did Anna get corr
Scilla [17]

Answer:

%88.88... and on and on

Formula Nonsense: percentage = b/l then *100 add % sign

so P= 32/36 so 0.888....*100= 88.88... so she made 88%

6 0
2 years ago
A laptop producing company also produces laptop batteries, and claims that the batteries
gregori [183]

Answer:

There is enough evidence to support the claim that the batteries power the laptops for significantly less than 4 hours. (P-value = 0).

The null and alternative hypothesis are:

H_0: \mu=4\\\\H_a:\mu< 4

Step-by-step explanation:

<em>The question is incomplete: To test this claim a sample or population standard deviation is needed.</em>

<em>We will estimate that the sample standard deviation is 2 hours, and use a t-test to test that claim.</em>

<em> NOTE (after solving): The difference between the sample mean and the mean of the null hypothesis is big enough to reject the null hypothesis, even when we have a sample standard deviation of 3.5 hours, which can be considered bigger than the maximum standard deviation for the sample.</em>

This is a hypothesis test for the population mean.

The claim is that the batteries power the laptops for significantly less than 4 hours.

Then, the null and alternative hypothesis are:

H_0: \mu=4\\\\H_a:\mu< 4

The significance level is 0.05.

The sample has a size n=500.

The sample mean is M=3.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{500}}=0.0894

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{3.5-4}{0.0894}=\dfrac{-0.5}{0.0894}=-5.5902

The degrees of freedom for this sample size are:

df=n-1=500-1=499

This test is a left-tailed test, with 499 degrees of freedom and t=-5.5902, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the batteries power the laptops for significantly less than 4 hours.

5 0
3 years ago
There are 63 students marching in a band, and they’re marching in 7 rows. How many students are in each row?
steposvetlana [31]
Total divided by number of rows=number per row
63/7=9
9 per row
3 0
3 years ago
Read 2 more answers
Let's say we have a sample of 57 participants in a study, what would the degrees of
fiasKO [112]

Answer:

56

Step-by-step explanation:

degree of freedom is n - 1, n being the sample size

One sample of 57 participants in a study (given)

For this study, n = 57

Using the degree of freedom formula, 57 - 1 = 56

Hope it helps, Let me know if yoy have any more questions/concerns !

Have a nice rest of your day :)

5 0
2 years ago
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