Answer: Choice A) 1990 to 1991
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Explanation:
Let's go through the answer choices one by one.
For choice A, we go from the year 1990 to 1991 which is a change of 1 year. The wage goes from 3.80 to 4.25 over this timespan, which is an increase of 4.25-3.80 = 0.45 dollars. Divide the change in wage (0.45 dollars) over the change in change in time (1 year) to get 0.45/1 = 0.45; this indicates that the wage increased by 0.45 dollars per year over the timespan 1990 to 1991
Now onto choice B. We have a wage increase of 3.80-3.35 = 0.45 over a course of 9 years (since 1990-1981 = 9) so 0.45/9 = 0.05 is the rate of wage growth, meaning that the wage bumps up by a nickel each year. So far choice A is the winner.
Moving onto choice C, we have a wage increase of 0.25 dollars (3.35-3.10 = 0.25) over an 1 year period (1981-1980 = 1) so the rate of change for this slice of time is 0.25/1 = 0.25 dollars per year. Choice A is still the winner.
Finally, for choice D, this is over a year as well (1980-1979 = 1) and the wage increases by 0.20 dollars (3.10-2.90 = 0.20) leading to a rate of change to be 0.20/1 = 0.20
So choice A has the largest rate of change which is the same as saying it has the largest rate of wage increase. This shows why choice A is the answer.
32.5 square feet. If you do the area formula “A=5v13(13) over 2”
Answer:
X^5+3x^4+81x+ 243
Step by step:
X^4*x=x^5
X^4*3=3x^4
81*x=81x
81*3=243
Answer:d. uniformly distributed variable
Step-by-step explanation:Uniform Distribution Definition- in statistics , this mean an outcome is equally likely each variable has an equal or same probability to appear in an outcome.
For example in a deck of cards ,they are uniformly distributed which means the likelihood of drawing a club, a diamond , and a heart is the same.
When we see the percentage of how these students are distributed in art college and business college it is likely that one obtains a uniform distributed results.
Answer:
D. y ≥ 2x – 2
Step-by-step explanation:
Graph the inequality by finding the boundary line, then shading the appropriate area.
y
≥
2
x
+
2
Graph the inequality by finding the boundary line, then shading the appropriate area.
y
≥
−
2
x
+
2
Graph the inequality by finding the boundary line, then shading the appropriate area.
y
≤
2
x
−
2
Graph the inequality by finding the boundary line, then shading the appropriate area.
y
≥
2
x
−
2
