The length of Ab & Df with work shown

Evaluate the Riemann sum for f(x) = 3 - 1/2 times x between 2 and 14 where the endpoints are included with six subintervals taki

Digiron [165]

Answer:

-6

Step-by-step explanation:

Given that :

we are to evaluate the Riemann sum for $f(x) = 3 - \dfrac{1}{2}x$ from 2 ≤ x ≤ 14

where the endpoints are included with six subintervals, taking the sample points to be the left endpoints.

The Riemann sum can be computed as follows:

$L_6 = \int ^{14}_{2}3- \dfrac{1}{2}x \dx = \lim_{n \to \infty} \sum \limits ^6 _{i=1} \ f (x_i -1) \Delta x$

where:

$\Delta x = \dfrac{b-a}{a}$

a = 2

b =14

n = 6

∴

$\Delta x = \dfrac{14-2}{6}$

$\Delta x = \dfrac{12}{6}$

$\Delta x =2$

Hence;

$x_0 = 2 \\ \\ x_1 = 2+2 =4\\ \\ x_2 = 2 + 2(2) \\ \\ x_i = 2 + 2i$

Here, we are using left end-points, then:

$x_i-1 = 2+ 2(i-1)$

Replacing it into Riemann equation;

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} \begin {pmatrix}3 - \dfrac{1}{2} \begin {pmatrix} 2+2 (i-1) \end {pmatrix} \end {pmatrix}2$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - (2+2(i-1))$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - (2+2i-2)$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 -2i$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 2i$

$L_6 = \lim_{n \to \infty} \sum \imits ^{6}_{i=1} 6 - 2 \lim_{n \to \infty} \sum \imits ^{6}_{i=1} i$

Estimating the integrals, we have :

$= 6n - 2 ( \dfrac{n(n-1)}{2})$

= 6n - n(n+1)

replacing thevalue of n = 6 (i.e the sub interval number), we have:

= 6(6) - 6(6+1)

= 36 - 36 -6

= -6

5 0

3 years ago

Find x Plz help me!!!!

lbvjy [14]

Find the total ° of the shape.
(5-2) x 180°= 540°

x+21°+x = 540°-105°-154°-88°
2x+21° = 193°
2x = 193°-21°
2x = 172°
x = 172° ÷ 2
x = 86°

8 0

3 years ago

Read 2 more answers

Please please help please please

vova2212 [387]

Answer:

transformation, cause you aren't altering it

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the best approximation of the area of a circle with a diameter of 17 meters? Use 3.14 to approximate pi. 53.4 m² 106.8 m

Arte-miy333 [17]

R = 17/2 =8.5 m
A = 3.14 x (8.5)^2
A = 3.14 x 72.25
A = 226.865

answer 226.9 m² (third choice)

8 0

3 years ago

When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither nu

o-na [289]

The answer would be A. When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither numerator determinant is zero, then the system has infinite solutions. It would be hard finding this answer when we use the Cramer's Rule so instead we use the Gauss Elimination. Considering the equations:

x + y = 3 and 2x + 2y = 6
Determinant of the equations are 
| 1 1 | 
| 2 2 | = 0

the numerator determinants would be
| 3 1 | . .| 1 3 | 
| 6 2 | = | 2 6 | = 0.
Executing Gauss Elimination, any two numbers, whose sum is 3, would satisfy the given system. For instance (3, 0), (2, 1) and (4, -1). Therefore, it would have infinitely many solutions.

3 0

3 years ago