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4 years ago

9/12 + 6/12 A. 1^1/3 B. 4/5 C. 5/8 D. 1^/14

1 answer:

5 0

I don't think you have the correct options. 9/12 + 6/12 = 15/12. To simplify, you divide each value by 3 and get 5/4, which, as a mixed number, would be 1 1/4, and neither 5/4 or 1 1/4 is an option. I hope this helps!

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If x = 1, y = 7, and z = 15, determine a number that when added to x, y, and z yields

almond37 [142]

You're looking for a number w such that the numbers

{1 + w, 7 + w, 15 + w}

form a geometric sequence, which in turn means there is a constant r for which

7 + w = r (1 + w)

15 + w = r (7 + w)

Solving for r, we get

r = (7 + w) / (1 + w) = (15 + w) / (7 + w)

Solve this for w :

(7 + w)² = (15 + w) (1 + w)

49 + 14w + w ² = 15 + 16w + w ²

2w = 34

w = 17

Then the three terms in the sequence are

{18, 24, 32}

and indeed we have 24/18 = 4/3 and 32/24 = 4/3.

6 0

3 years ago

Hi everyone can someone please help with this problem?

MAVERICK [17]

It gotta be c but it was kinda hard to c even when i close

8 0

3 years ago

Please help!!! Greatly apprecieted!

Lilit [14]

Answer:

Tiffany has 13 dimes and 4 nickels.

Step-by-step explanation:

To solve this problem, you will need to write a systems of equations, n will be the number of nickels and d will be the number of dimes.

n+d=17 This means that the number of nickels plus the number of dimes is equal to 17.

5n+10d=150, This means that for each nickel, there is 5 cents and for each dime, there is 10 cents. The equation is equal to 150 cent because the coins are worth 150 cents.

Next, solve the system:

n+d=17

5n+10d=150 First simplify the second equation by dividing it all by 5.

n+d=17

n+2d=30, Next, isolate n to use substitution on the system.

n=17-d

n=30-2d, Substitute n to solve for d

17-d=30-2d, Solve for d

d=13, this means that there are 13 dimes, plug in the d value in either of the equations to find n.

n+(13)=17

n=4, There are 4 nickles

3 0

3 years ago

How do find the domain and range of <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7Bx-8%7D%7D" id="TexFormula1" tit

Kisachek [45]

$\sqrt{x-8}$ is undefined if the argument $x-8$ is negative, so you first need to require that

$x-8\ge0\implies x\ge8$

We're not done yet, though, because $\dfrac1{\sqrt{x-8}}$ still doesn't exist when $x=8$ , so we remove this from the domain and we're left with $x>8$ , or in interval notation, $(8,\infty)$

To find the range, consider the limits of the function as you approach either endpoint of the domain.

$\displaystyle\lim_{x\to8^+}\frac1{\sqrt{x-8}}=+\infty$
$\displaystyle\lim_{x\to\infty}\frac1{\sqrt{x-8}}=0$

Since $\dfrac1{\sqrt{x-8}}$ is positive everywhere, the range is $(0,\infty)$

3 0

3 years ago

How do you graph y > 25 + 10 x ?

liubo4ka [24]

Answer:

Step-by-step explanation:

huh The number 2 goes into both 12 and 14.

Step-by-step explanation:

12 ÷ 2 is 6 and 14 ÷2 is 7 . You can't really simplify 14 by any other whole number besides 2 or 7 .

8 0

4 years ago