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tangare [24]
3 years ago
7

Please help me, which of the following sets of ordered pairs is a function?

Mathematics
1 answer:
Anni [7]3 years ago
4 0
Function means no x value repepetes with a differnt y value
(x,y)
first numbers never repeat


first one, the x values repeat
2nd, x values rpeat
3rd, no repeat
4th, -3 repeats

answer is 3rd option
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A triangle has a base length of 14cm greater than its height . If the area of the triangle is 48cm^2, find the height of the tri
irga5000 [103]
Area of triangle = base x height /2
48 = (a+14)a/2
a^2 +14a = 96
a^2 + 14a - 96 = 0
Solving for a = 5.04
5 0
3 years ago
Please help me and pls do both
Nana76 [90]

Answer:

7/36

Step-by-step explanation:

find the LCD   write all the numerators above the least common denominator

LCD is 36

4 +3 /36 =7/36

3 0
3 years ago
Evaluate csc (3pi/14) and cot (5pi/12) using a calculator.
ELEN [110]
The drop down answers are
csc= 1.604
cot= .268
5 0
3 years ago
Select all the correct answers. If the measure of angle 0 is 5(pi)/4, which statements are true?
elixir [45]

Finding the equivalent angle of \theta, the correct statements are given as follows:

  • The Measure of the reference angle is 45.
  • \cos{\theta} = \frac{\sqrt{2}{2}}.
  • \tan{\theta} = 1
  • \sin{\theta} = \frac{\sqrt{2}{2}}.

<h3>What are equivalent angles?</h3>

Each angle on the second, third and fourth quadrants will have an equivalent on the first quadrant.

In this problem, the given angle is as follows:

\theta = \frac{5\pi}{4}

It is on the third quadrant, as it is between pi and 1.5 pi, hence the equivalent on the first quadrant, also known as the reference angle, is given by:

\frac{5\pi}{4} - \pi = \frac{5\pi}{4} - \frac{4\pi}{4} = \frac{\pi}{4}

The angle of 45º has equal sine and cosine, and tangent of 1, hence the correct statements are:

  • The Measure of the reference angle is 45.
  • \cos{\theta} = \frac{\sqrt{2}{2}}.
  • \tan{\theta} = 1
  • \sin{\theta} = \frac{\sqrt{2}{2}}.

More can be learned about equivalent angles at brainly.com/question/24787111

#SPJ1

8 0
1 year ago
a car starts from rest and travels for 5.0s with a uniform acceleration of 1.5 m/s^2. what is the final velocity of the car? how
AfilCa [17]
V = u + at
u = 0 
v = 0 + 1.5*5
v = 7.5 m/s
final velocity is 7.5 m/s

s = ut + 0.5at^2
s = 0 + (0.5*1.5*5^2)
s = (0.5*1.5*25)
s = 18.75 m
total travel distance is 18.75 m.
5 0
3 years ago
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