$(h+k)(x)=h(x)+k(x)\\\\\bold{METHOD\ 1:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(k+h)(2)=h(2)+k(2)\\\\\text{Calculate}\ h(2)\ \text{and}\ k(2).\\\text{Put}\ x=2\ \text{to the equations of the functions}\\\\h(2)=2^2+1=4+1=5\\k(2)=2-2=0\\\\\text\\\\\text{Substitute:}\\\\(h+k)(2)=5+0=5$

$\bold{METHOD\ 2:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(h+k)(x)=h(x)+k(x)=(x^2+1)+(x-2)=x^2+x-1\\\\(h+k)(2)-\text{put}\ x=2\\\\(h+k)(2)=2^2+2-1=4+2-1=6-1=5$

5 0

2 years ago

What is the eighth term in the pattern 2,10, 18,26,

Oksana_A [137]

The 8th character would be 58

5 0

2 years ago

What is the distance between the following points?

Anastasy [175]

Answer:

distance = 5

Step-by-step explanation:

Use Pythagorean Theorem or Distance Formula (which comes from Pythagorean Thm anyway) see image.

6 0

2 years ago

(2a 2 + a + 3) (a - 1) Please help

ArbitrLikvidat [17]

Hey there!

You can use distributive property, as I mentioned in your previous questions.

multiply...
2a² × a = 2a³
2a² × -1 = -2a²
a × a = a²
a × -1 = -a
3 × a = 3a
3 × -1 = -3

add all those terms..
2a³ - 2a² + a² - a + 3a - 3
add the like terms

2a³ - a² + 2a - 3

Hope this helped :)

4 0

2 years ago

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