8x+6+4= 3x- 2x- 4 is the correct step
Answer:5
Step-by-step explanation:
I said that because I just divide
Answer:
The equation in point - slope form of a line that passes through the points (3,-5) and (-8,4) is: y-(-5) = -(9/11) (x-3) or y+5 = -(9/11) (x-3)
Step-by-step explanation:
P1=(3,-5)=(x1,y1)→x1=3, y1=-5
P2=(-8,4)=(x2,y2)→x2=-8, y2=4
Equation in Point-Slope Form: y-y1=m(x-x1)
Slope: m=(y2-y1)/(x2-x1)
Replacing the known values:
m=[4-(-5)] / (-8-3)
m=(4+5) / (-11)
m=(9) / (-11)
m=-(9/11)
Equation in the point - slope form:
y-(-5) = -(9/11) (x-3)
y+5 = -(9/11) (x-3)
Answer:
(-6, -5)
Step-by-step explanation:
Reflection across the y-axis leaves the point on the same horizontal line, but with the sign of its x-coordinate changed.
(x, y) ⇒ (-x, y) . . . . . reflection across the y-axis
(6, -5) ⇒ (-6, -5)
The image point is (-6, -5).
Answer:
(a) B. G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.
(b) Every function of the form
is an antiderivative of 8x
Step-by-step explanation:
A function <em>F </em>is an antiderivative of the function <em>f</em> if

for all x in the domain of <em>f.</em>
(a) If
, then
is an antiderivative of <em>f </em>because

Therefore, G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.
Let F be an antiderivative of f. Then, for each constant C, the function F(x) + C is also an antiderivative of <em>f</em>.
(b) Because

then
is an antiderivative of
. Therefore, every antiderivative of 8x is of the form
for some constant C, and every function of the form
is an antiderivative of 8x.