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grigory [225]
3 years ago
11

Find a solution to the equation without writing anything down. x+1=5

Mathematics
2 answers:
elixir [45]3 years ago
8 0
X equals 4, because 4+1= 5
Reptile [31]3 years ago
6 0

Answer:

4

Step-by-step explanation:

5-1=4

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A rectangle has a length that is three feet more than twice it’s width. If the area of the rectangle is 90 square feet, then alg
Mkey [24]

Answer:

Length=27feet\\Width=12 feet

Step-by-step explanation:

Let, the length of the rectangle be 'L'

and, width of the rectangle be 'W'

length=2*Width+3

L=(2W+3) feet\\\\

Area of the rectangle= 90 square feet

Area of a rectangle = Length*Width

90=(2W+3)*W\\\\2W^2+3W=90\\\\2W^2+3W-90=0\\\\

Using Factorization Method to solve quadratic equation:

2W^2-12W+15W-90=0

Taking common from the equation:

2W(W-12)+15(W-12)=90\\\\(W-12)(2W+15)=0\\\\W-12=0\\\\W=12 feet

OR

2W+15=0\\\\2W=-15\\\\W=-7.5 feet

The Width cannot be negative, therefore Width(W)=12 feet

Length=2*Width+3\\\\=(12*2)+3\\\\=24+3\\\\=27 feet

Length=27feet\\Width=12 feet

3 0
3 years ago
I will mark you brainliest and give 50 points if u help and pls I want the answer to both a and b if u give random answers witho
shusha [124]

Answer:

5a. 4w+24≤100

5b. Dimensions=31ft x 19 ft

      Area = 589ft²

Step-by-step explanation:

l=w+12

p=2l+2w

p=2(w+12)+2w

p=2w+24+2w

p=4w+24

The farmer has 100ft of fencing, so maximum that the perimeter (p) can be is 100, meaning (4w+24) has to be less than or equal to 100:

4w+24≤100

For the largest possible perimeter, all 100 of fencing will be used, so allow 100 to be equal to 4w+24)

100=4w+24

4w=76

w=19ft

l=w+12

l=19+12

l=31ft

The dimensions are 31ft x 19ft.

Area=lw

=31*19

=589ft²

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3 years ago
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Answer:

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Step-by-step explanation:

i did the test

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3 years ago
If a cat catches 120 mice in 30 days,how many mice does it catch in 5 days?​
Elanso [62]

Answer:

ITS 24

Step-by-step explanation:

divide it 120÷4=24

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3 years ago
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Differences between Prokaryotic and Eurkaryotic Cells?
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