You're given that φ is an angle that terminates in the third quadrant (III). This means that both cos(φ) and sin(φ), and thus sec(φ) and csc(φ), are negative.
Recall the Pythagorean identity,
cos²(φ) + sin²(φ) = 1
Multiply the equation uniformly by 1/cos²(φ),
cos²(φ)/cos²(φ) + sin²(φ)/cos²(φ) = 1/cos²(φ)
1 + tan²(φ) = sec²(φ)
Solve for sec(φ) :
sec(φ) = - √(1 + tan²(φ))
Given that cot(φ) = 1/4, we have tan(φ) = 1/cot(φ) = 1/(1/4) = 4. Then
sec(φ) = - √(1 + 4²) = -√17
Answer:
The equation of line AB with points (3,3) and (-3,5) is given as
: x + 3y = 12
Step-by-step explanation:
Here, the given points are A (3, 3) and B (-3,5).
Now, slope of any line is given as :
or, 
Hence, the slope of the line AB is (-1/3)
Now , A POINT SLOPE FORM of an equation is
(y - y0) = m (x - x0) ; (x0, y0) is any arbitrary point on line.
So, for the point (3,3) the equation of the line is
y - 3
Hence, the equation of line AB with points (3,3) and (-3,5) is given as:
x + 3y = 12
Answer: QE = 10
Step-by-step explanation: To solve this problem, it's important to understand that the diagonals of a parallelogram bisect each other.
This means that E is the midpoint of diagonal SQ.
So we can setup the equation x² + 9x = 4x + 6.
To solve this polynomial equation, set it equal to zero first.
So we have x² + 5x - 6 = 0 and we get (x + 6)(x - 1) = 0
when we factor the left side of the equation.
So this means that x = -6 or x = 1.
However, -6 will give us a negative length when we plug it in
to find QE so this will not work.
However, plugging 1 in will give us 10 as a length so QE = 10.
100 meters is -1°C
1,000 meters is -10°C
10,000 meters is -100°C
And 2,000 meters is -20°C
12Km is 12,000 meters
12,000 meters is -120°C
Your answer is -120°C
-IronWolfX
Answer: 105 miles?
I am not sure but that"s what I got
Step-by-step explanation:
