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Neporo4naja [7]
3 years ago
9

Imagine you are a civil engineer who designs buildings. How might testing small-scale building models or their components be hel

pful in testing improvements and changes to the building design? Please explain your answer.
PLS HELP ME
Chemistry
2 answers:
DochEvi [55]3 years ago
7 0
The answer would be 40 cm
lubasha [3.4K]3 years ago
3 0
The error would be 40 cm
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Which of the following is a valid mole ratio from the balanced equation 2C3H6 + 902 - 6CO2 + 6H20? (4 points)
erastovalidia [21]

Answer:

6 mol H, 9 mol O2

Explanation:

We can see that in water, there are 6 moles of hydrogen, and for oxygen, there is 9 moles

6 0
3 years ago
Which model failed to explain the
11Alexandr11 [23.1K]

Answer:

C). The Bohr-Rutherford model

Explanation:

The 'Bohr-Rutherford model' of the atom failed to elaborate on the attraction between some substances. It essentially targeted hydrogen atoms and failed to explain its stability across multi-electrons. The nature and processes of the chemical reactions remained unillustrated and thus, this is the key drawback of this model. Thus, <u>option C</u> is the correct answer.

5 0
3 years ago
From the deepest to the surface, what are the parts of the earths interior
xz_007 [3.2K]
The answer is core- mantle - crust :)
7 0
3 years ago
Read 2 more answers
For the following H30 concentration list the pH and the OH concentration in
Alenkinab [10]

Answer:

[H3O+] = 1.4*10^-5 M

pH = 4.85

[OH-] = 7.08*10^-10

Explanation:

As pH is a measure of hydronium H3O concentration, simply substitute [H3O+] into the following equation:
pH = -log[H+]
pH = -log(1.4*10^-5)
pH = 4.853871...
Round to 2-3 sig figs due to only being given data with 2 significant figures
pH = 4.85

One method to get to [OH-] is to turn pH into pOH and then use inverse functions to get [OH-]
pH + pOH = 14
4.85 + pOH = 14
pOH = 9.15

Then to get [OH-] from pOH:
pOH = -log[OH-]
9.15 = -log[OH-]
-9.15 = log[OH-]
10^(-9.15) = [OH-]
7.07945784 * 10^-10 = [OH]
Round based on given significant figures again:
7.08*10^-10 = [OH-]

(Feel free to add any questions & I'll be sure to reply if clarification is needed)

6 0
2 years ago
Read 2 more answers
A sample of an ideal gas at 1.00 atm and a volume of 1.82 L was placed in a weighted balloon and dropped into the ocean. As the
Anvisha [2.4K]

Answer:

The answer to your question is Volume = 0.12 L

Explanation:

- Data

Pressure 1 = 1 atm

Volume 1 = 1.82 L

Pressure 2 = 15 atm

Volume 2 = ?

Temperature = constant

- Formula

- To solve this problem use the Boyle's law

            P1V1 = P2V2

- Solve for V2

            V2 = P1V1 / P2

- Substitution

             V2 = (1)(1.82) / 15

- Simplification

             V2 = 1.82 / 15

- Result

             V2 = 0.12 L

3 0
3 years ago
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