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ahrayia [7]
3 years ago
12

A 1.00-L flask was filled with 2.00 moles of gaseous SO2 and 2.00 moles of gaseous NO2 and heated. After equilibrium was reached

, it was found that 1.30 moles of gaseous NO was present. Assume that the reaction SO2 1 g2 1 NO2 1 g2mSO3 1 g2 1 NO1 g2 occurs under these conditions. Calculate the value of the equilibrium constant, K, for this reaction.
Chemistry
1 answer:
antiseptic1488 [7]3 years ago
6 0

Answer:

K = 3.45

Explanation:

In the reaction:

SO₂(g) + NO₂(g) ⇄ SO₃(g) + NO(g)

And K is:

K = [SO₃] [NO] / [SO₂] [NO₂]

<em>Where [] are concentrations in equilibrium, as volume is 1L, [] could be taken as moles.</em>

Equilibrium concentrations are:

[SO₂] = 2.00 moles - X

[NO₂] = 2.00 moles - X

[SO₃] = X

[NO] = X

AS moles of NO are 1.3 moles, X = 1.3 moles

Replacing:

[SO₂] = 0.7 moles = 0.7M

[NO₂] = 0.7M

[SO₃] = 1.3M

[NO] = 1.3M

K = 1.3M² / 0.7M²

<h3>K = 3.45</h3>

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Answer:

<em>A solution containing 60 grams of nano3 completely dissolved in 50. Grams of water at 50°c is classified as being</em> <u>supersaturaded</u>

Explanation:

This question is about solubility.

Regarding solubility, the solutions may be classified as:

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Each substance has its own, unique solubility properties. So, in order to tell the state of the solution you need to compare with either solubility tables, or solubility curves; or run you own experiments.

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<em />

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