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Anon25 [30]
4 years ago
8

A 5-column table with 2 rows. Column 1 is labeled number of protons, with entries A and D; column 2 is number of neutrons, with

entries 7 and E; Column 3 is atomic number, with entries B and 26; Column 4 is Mass Number, with entries 15 and 56, and Column 5 is Element (symbol) with entries C and F. Using the periodic table, complete the table to describe each atom. Type in your answers.
Chemistry
1 answer:
pogonyaev4 years ago
5 0

Answer:

A = 8

B = 8

C = Oxygen (O)

D = 26

E = 30

F = Iron (Fe)

Explanation:

protons    neutrons    atomic number    mass number     element

A               7                 B                           15                        C

D               E                 26                         56                       F

mass number = protons + neutrons

E = 56 - 26 = 30

A = 15 - 7 = 8

protons = atomic number

B = 8

D = 26

From atomic number:

C = Oxygen (O)

F = Iron (Fe)

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I have 250 mL of an acid. If a friend gives me another 75 mL of the same acid, how much will I have?
Zigmanuir [339]

Answer:325 mL of acid

Explanation:250 mL + 75 mL = 325 mL

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2 years ago
65 million years ago there was a mass extinction that is best known for killing the dinosaurs. There was also a large
Brilliant_brown [7]

Answer:

65 million years ago there was a mass extinction that is best known for killing the dinosaurs. There was also a large

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Explanation:

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3 years ago
Copper has two naturally occurring isotopes, 63Cu Gsotopic mass 629396 arnu) and 65Cu Osotopic mass 64.9278 amu). If copper has
madam [21]

<u>Answer:</u> The percentage abundance of _{29}^{63}\textrm{Cu} and _{29}^{65}\textrm{Cu} isotopes are 75.77% and 24.23% respectively

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{29}^{63}\textrm{Cu} isotope be 'x'. So, fractional abundance of _{29}^{63}\textrm{Cu} isotope will be '1 - x'

  • <u>For _{29}^{63}\textrm{Cu} isotope:</u>

Mass of _{29}^{63}\textrm{Cu} isotope = 62.9396 amu

Fractional abundance of _{29}^{63}\textrm{Cu} isotope = x

  • <u>For _{29}^{65}\textrm{Cu} isotope:</u>

Mass of _{29}^{65}\textrm{Cu} isotope = 64.9278 amu

Fractional abundance of _{29}^{65}\textrm{Cu} isotope = 1 - x

  • Average atomic mass of copper = 63.546 amu

Putting values in equation 1, we get:

63.546=[(62.9396\times x)+(64.9278\times (1-x))]\\\\x=0.6950

Percentage abundance of _{29}^{63}\textrm{Cu} isotope = 0.6950\times 100=69.50\%

Percentage abundance of _{29}^{65}\textrm{Cu} isotope = (1-0.6950)=0.305\times 100=30.50\%

Hence, the percentage abundance of _{29}^{63}\textrm{Cu} and _{29}^{65}\textrm{Cu} isotopes are 69.50% and 30.50% respectively.

4 0
3 years ago
What would be the volume, in liters measured at STP, of 0.56 moles of carbon monoxide?
sertanlavr [38]

Answer:

"This conversions relies on the fact that a mole of gas at STP has a volume of 22.4 L. It is important to note, however, that if the conditions of the gas are different this conversion will NOT work. Under those conditions you must use the ideal gas law to convert between moles and liters."

5 0
3 years ago
Calculate the number of moles of BaF2 in a 10.0 g sample of BaF2.
UkoKoshka [18]

Answer:

The number of moles = 0.06 moles

Explanation:

i) Formula

Number of moles = Mass of the sample ÷ Molar masses of the substances

ii) Number of moles = 10.0 ÷ (137)+(19×2)

= 10.0 ÷ 175

= 0.06 moles

5 0
4 years ago
Read 2 more answers
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