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Anon25 [30]
3 years ago
8

A 5-column table with 2 rows. Column 1 is labeled number of protons, with entries A and D; column 2 is number of neutrons, with

entries 7 and E; Column 3 is atomic number, with entries B and 26; Column 4 is Mass Number, with entries 15 and 56, and Column 5 is Element (symbol) with entries C and F. Using the periodic table, complete the table to describe each atom. Type in your answers.
Chemistry
1 answer:
pogonyaev3 years ago
5 0

Answer:

A = 8

B = 8

C = Oxygen (O)

D = 26

E = 30

F = Iron (Fe)

Explanation:

protons    neutrons    atomic number    mass number     element

A               7                 B                           15                        C

D               E                 26                         56                       F

mass number = protons + neutrons

E = 56 - 26 = 30

A = 15 - 7 = 8

protons = atomic number

B = 8

D = 26

From atomic number:

C = Oxygen (O)

F = Iron (Fe)

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Complete Question

Magnesium sulfate forms a hydrate with the formula MgSO_4. 7H_20. What is the maximum amount of water (in grams) that can be removed from 15 ml of toluene by the addition of 200 mg of anhydrous magnesium sulfate? The molar mass of MgSO_4 is 120.4 g/mol; H20 = 18 g/mol.

Answer:

The value  is  z =  0.2093 \  g of  H_2O

Explanation:

From the question we are told that

   The volume of toluene is  V = 15 mL

    The mass of  anhydrous magnesium sulfate is  m =  200m g  = 200 *10^{-3} \  g

   The formula of the hydrate is   MgSO_4. 7H_20

    The molar mass of   MgSO_4  is  z =120.4 \ g/mol

From the formula given we see that

  1 mole of  Mg SO_4 wil remove  7 moles of H_2O to for the given formula

Hence

  120.4 g (1 mole) will remove  7 moles (7 * 18 g = 126 g  ) of  H_2O to for the given formula

Therefore 1 g of  Mg SO_4  x g  of  H_2O  

So

     x  =  \frac{x]126 *  1}{ 120.4 }

=>     x  =  1.0465 \  g

From our calculation we obtained that

  1 g of Mg SO_4 will remove  x  =  1.0465 \  g  of  H_2O  

Then  

   200 *10^{-3} \  g of Mg SO_4 will remove z g of  x  =  1.0465 \  g  of  H_2O  

So

   z =  200 *10^{-3} *  1.0465

=>z =  200 *10^{-3} *  1.0465

=>z =  0.2093 \  g of  H_2O  

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