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STALIN [3.7K]
3 years ago
7

A circle has an 18-inch radius and a shaded sector with a central angle of 50°. Determine the area of the shaded sector.

Mathematics
1 answer:
Makovka662 [10]3 years ago
3 0

Answer:

Area of shaded region is 141.3 square inches

Step-by-step explanation:

It is given that,

A circle has an 18-inch radius and a shaded sector with a central angle of 50°

Area of circle = πr²

<u>To find the area of circle</u>

Area of circle = πr² = 3.14*18²  = 3.14 * 18 * 18

Area =  1017.36 square inches

<u>To find the part of shaded region</u>

central angle of shaded region is 50°.

part of sector = 50/360 = 5/36

<u>To find the area of shaded region</u>

area of shaded region is 5/36th of total area of circle

Area of shaded region = 5/36(1017.36) = 141.3 square inches

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Step-by-step explanation:

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Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.
Maru [420]

Answer:

9\text{ln}|x|+2\sqrt{x}+x+C

Step-by-step explanation:

We have been an integral \int \frac{9+\sqrt{x}+x}{x}dx. We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx

\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx

Now, we will apply the sum rule of integrals as:

\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx

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Using common integral \int \frac{1}{x}dx=\text{ln}|x|, we will get:

9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx

Now, we will use power rule of integrals as:

9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx

9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx

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We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

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4 0
3 years ago
How do you solv this step by step and explain and help me get the answers
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Answer:

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Step-by-step explanation:

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3 years ago
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nignag [31]

Answer:

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Step-by-step explanation:

Writing the description in algebraic translation

\frac{b^{-2}}{ab^{-3}}

so we have to find the expression which will be equal to \frac{b^{-2}}{ab^{-3}}.

Considering the expression

\frac{b^{-2}}{ab^{-3}}

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\frac{b^{-2}}{b^{-3}}=b^{-2-\left(-3\right)}

so the expression becomes

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=\frac{b}{a}

Therefore,

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7 0
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