About 0.92 kg of benzyl salicylate would be needed in order to manufacture 325 tubes of sunscreen.
A tube contains 4.0 oz of the sunscreen and each one 2.5% benzyl salicylate.
2.5% of 4.0 oz = 0.1 oz
Thus, each tube would need 0.1 oz of benzyl salicylate.
325 tubes of the sunscreen is needed and each one requires 0.1 oz of benzyl salicylate. Hence, total amount of benzyl salicylate needed would be:
325 x 0.1 oz = 32.5 oz
From conversion:
16 oz = 1 lb
Hence,
32.5 oz = 32.5/16
= 2.03 lb
Also:
2.205 lb = 1 kg
2.03 lb = 2.03/2.205
= 0.92 kg
More on dimensional analysis can be found here: brainly.com/question/22015862
Answer:
A. Methanol
B. 2-chloropropan-1-ol
C. 2,2-dichloroethanol
D. 2,2-difluoropropan-1-ol
Explanation:
Primary alcohols are stronger acids than secondary alcohols which are stronger than tertiary alcohols.
This trend is so because of the stability of the alkoxide ion formed(stabilising the base, increases the acidity). A more stabilised alkoxide ion is a weaker conjugate base (dissociation of an acid in water).
By electronic factors, When there are alkyl groups donating electrons, the density of electrons on th O- will increase a d thereby make it less stable.
By stearic factors, More alkyl group bonded to the -OH would mean the bulkier the alkoxide ion which would be harder to stabilise.
Down the group of the periodic table, basicity (metallic character) decreases as we go from F– to Cl– to Br– to I– because that negative charge is being spread out over a larger volume that is electronegativity decreases down the group.
Electronegative atoms give rise to inductive effect and a decrease in indutive effects leads to a decrease in acidity. Therefore an Increasing distance from the -OH group lsads to a decrease in acidity.
From above,
A. Methanol
B. 2-chloropropan-1-ol
C. 2,2-dichloroethanol
D. 2,2-difluoropropan-1-ol
I believe it is D.
Since something with a high temperature has a higher kinetic energy, it would make sense for the energy of the molecules in the ground to increase. This is because the increasing temperature of the ground allows for the molecules to become faster in motion.
<u>Answer:</u> The molar mass of the unknown protein is 6387.9 g/mol
<u>Explanation:</u>
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
or,
where,
= osmotic pressure of the solution = 0.0766 atm
i = Van't hoff factor = 1 (for non-electrolytes)
Mass of protein = 100. mg = 0.100 g (Conversion factor: 1 g = 1000 mg)
Molar mass of protein = ?
Volume of solution = 5.00 mL
R = Gas constant = 
T = temperature of the solution = ![25^oC=[25+273]K=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B25%2B273%5DK%3D298K)
Putting values in above equation, we get:
Hence, the molar mass of the unknown protein is 6387.9 g/mol
