Answer: -
Rimmed steel does not contain nickel.
Explanation: -
Rimmed steel is a deoxidised low carbon steel. Deoxidation leads to formation of rims in the iron.
Carbon, sulfur and phosphorus is present in rimmed steel. The concentrations of these vary from the outer rim to the inner rim. It is not as tough as other steel.
Hence it is primarily used for products where a lot of bending is required. Thus Rimmed steel does not contain nickel.
Answer:
HCN
Explanation:
Acids are the species which furnish hydrogen ions in the solution or is capable of forming bonds with electron pair species as they are electron deficient species.
When an acid donates a proton, it changes into a base which is known as its conjugate base.
Bases are the species which furnish hydroxide ions in the solution or is capable of forming bonds with electron deficient species as they are electron rich species. When a base accepts a proton, it changes into a acid which is known as its conjugate acid.
The acid and the base which is only differ by absence or presence of the proton are known as acid conjugate base pair.
Also, the strongest acid leads to the weakest conjugate base and vice versa.
Thus, Out of HI, HCN, 
, 
and HCl , the weakest acid is:- HCN
<u>Thus, HCN corresponds to the strongest conjugate base. </u>
The answer is actually Neptune, if you dont believe me look it up.
Answer:
pH = 12.61
Explanation:
First of all, we determine, the milimoles of base:
0.120 M = mmoles / 300 mL
mmoles = 300 mL . 0120 M = 36 mmoles
Now, we determine the milimoles of acid:
0.200 M = mmoles / 100 mL
mmoles = 100 mL . 0.200M = 20 mmoles
This is the neutralization:
HCOOH + OH⁻ ⇄ HCOO⁻ + H₂O
20 mmol 36 mmol 20 mmol
16 mmol
We have an excess of OH⁻, the ones from the NaOH and the ones that formed the salt NaHCOO, because this salt has this hydrolisis:
NaHCOO → Na⁺ + HCOO⁻
HCOO⁻ + H₂O ⇄ HCOOH + OH⁻ Kb → Kw / Ka = 5.55×10⁻¹¹
These contribution of OH⁻ to the solution is insignificant because the Kb is very small
So: [OH⁻] = 16 mmol / 400 mL → 0.04 M
- log [OH⁻] = pOH → 1.39
pH = 14 - pOH → 12.61
Answer: Albedo
Explanation:
((Earth's normal albedo is about 0.3.)))
At the end of the day, around 30 percent of approaching sunlight based radiation is reflected go into space and 70 percent is consumed.
