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3 years ago

Which of the following acids will have the strongest conjugate base?HIHCNHNO3HClO4HCl

Chemistry

1 answer:

Andrej [43]3 years ago

7 0

Answer:

HCN

Explanation:

Acids are the species which furnish hydrogen ions in the solution or is capable of forming bonds with electron pair species as they are electron deficient species.

When an acid donates a proton, it changes into a base which is known as its conjugate base.

Bases are the species which furnish hydroxide ions in the solution or is capable of forming bonds with electron deficient species as they are electron rich species. When a base accepts a proton, it changes into a acid which is known as its conjugate acid.

The acid and the base which is only differ by absence or presence of the proton are known as acid conjugate base pair.

Also, the strongest acid leads to the weakest conjugate base and vice versa.

Thus, Out of HI, HCN, $HNO_3$ , $HClO_4$ and HCl , the weakest acid is:- HCN

<u>Thus, HCN corresponds to the strongest conjugate base. </u>

You might be interested in

A student conducting the iodine clock experiment accidentally makes an S2O32- stock solution that is too concentrated. How will

zysi [14]

The question is incomplete the complete question is :

Reaction 1: 3I⁻ (aq) + S₂O₈²⁻ (aq) → I₃⁻ (aq) + 2SO₄²⁻ (aq) slow

Reaction 2: I₃⁻ (aq) + 2S₂O₃²⁻ (aq) → 3I⁻ (aq) + S₄O₆²⁻ (aq) fast

Reaction 3: I₃⁻ (aq) + starch (aq) → 3I⁻ ---- starch (bluish black) fast

A. Not all of the 2S₂O₃²⁻ will react, which will increase the calculated rate.

B. Not all of the 2S₂O₃²⁻ will react, which will decrease the calculated rate.

C. It will take longer for the color to change, as the reaction takes longer when more reactant is present.

D. It will take less time for the color to change, as rate increases with concentration of reactant.

Answer: Option D

Explanation:

The reaction time for the experiment will be reduced because the concentrated form of S2O32- reacts very fast with the iodine solution.

The color will change very fast as the reactant is concentrated.Also, the reaction rate(K) of this step would occur faster than the original rate.

This is based on Le Chatelier's Prinicple which states that a corresponding change would happen to the equilibrium of a reaction when pressure, concentration of the substances or temperature is changed.

Here, the concentration has changed.

4 0

3 years ago

What is the mass in grams of carbon dioxide that would be required to react with 75.8 g of LiOH in the following chemical reacti

Advocard [28]

Answer:

69.6 g CO₂

Explanation:

To find the mass of carbon dioxide, you need to (1) convert grams LiOH to moles LiOH (via molar mass from periodic table values), then (2) convert moles LiOH to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (desired unit in the numerator). The final answer should have 3 sig figs to reflect the given value's sig figs.

Molar Mass (LiOH): 6.9410 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (LiOH): 23.947 g/mol

2 LiOH(s) + 1 CO₂(g) ----> Li₂CO₃(s) + H₂O(l)

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

75.8 g LiOH 1 mole 1 mole CO₂ 44.007 g
------------------ x ---------------- x ----------------------- x ------------------- =
23.947 g 2 moles LiOH 1 mole

= 69.6 g CO₂

5 0

3 years ago

Which halogen is the most easily oxidized?

Tanya [424]

The Halogen that is most likely easy to be oxidised would be the Iodine. In addition, the property that makes the Iodine ideal for oxidation is due to the fact that its d-orbital contains more electrons compared to other halogens such as fluorine where oxidation would tend to be difficult to occur on the element.

5 0

3 years ago

How many grams of copper (II) fluoride, CuF2, are needed to make 5.1 liters of a 1.4M solution?

Alexus [3.1K]

Answer: 724.71 grams

Explanation:

Volume of solution (v) = 5.1 liters

Concentration of solution (c) = 1.4M

Amount of CuF2 needed (n) = ?

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

make n the subject formula

n = c x v

n = 1.4M x 5.1 Liters

n = 7.14 moles

Since, 7.14 moles of CuF2 (n) is needed, use the molar mass of CuF2 to get the mass in grams.

The atomic masses of Copper = 63.5g;

and Fluorine = 19g

So, I CuF2 = 63.5g + (19g x 2)

= 63.5g + 38g

= 101.5g/mol

Then, apply the formula

Number of moles = mass in grams / molar mass

7.14 moles = m / 101.5 g/mol

m = 7.14 moles x 101.5 g/mol

m = 724.71g

Thus, 724.71 grams of copper (II) fluoride, CuF2, are needed to make 5.1 liters of a 1.4M solution

7 0

4 years ago

If the temperature is kept constant, what change in volume would cause the pressure of an enclosed gas to be reduced to one-th

joja [24]

Using the ideal gas equation pV = nRT, where R is the ideal gas constant, we can show that p=nRT/V. Since n, R and T are all constants, p2/p1 = V1/V2 where p1 and p2 are the start and final pressures respectively and V1 and V2 are the start and final volumes respectively. For if p1 = 3*p2, the pressure would have fallen to one third of its original value, and it follows that V2 = 3*V1. Therefore, for the pressure to fall to a third of its original value, the volume must increase by a factor of 3.

3 0

3 years ago