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Vlada [557]
3 years ago
13

Calculate the pH in titration of a weak acid: What is the pH in titration of formic acid (HCHO2, 0.200 M, 100.0 mL) after the ad

dition of 300.0 mL NaOH (0.120 M)? The Ka of formic acid is 1.799 x 10-4.
Chemistry
1 answer:
ki77a [65]3 years ago
6 0

Answer:

pH = 12.61

Explanation:

First of all, we determine, the milimoles of base:

0.120 M = mmoles / 300 mL

mmoles = 300 mL . 0120 M = 36 mmoles

Now, we determine the milimoles of acid:

0.200 M = mmoles / 100 mL

mmoles = 100 mL . 0.200M = 20 mmoles

This is the neutralization:

HCOOH    +     OH⁻         ⇄        HCOO⁻     +    H₂O

20 mmol       36 mmol             20 mmol

                    16 mmol

We have an excess of OH⁻, the ones from the NaOH and the ones that formed the salt NaHCOO, because this salt has this hydrolisis:

NaHCOO  →  Na⁺  +  HCOO⁻

HCOO⁻  +  H₂O  ⇄   HCOOH  +  OH⁻   Kb →  Kw / Ka = 5.55×10⁻¹¹

These contribution of OH⁻ to the solution is insignificant because the Kb is very small

So:  [OH⁻] =  16 mmol / 400 mL →  0.04 M

- log  [OH⁻]  = pOH →  1.39

pH = 14 - pOH → 12.61

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If 110g of copper sulphate is present in 550g of solution calculate the concentration of solution
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Answer:

20%

Explanation:

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mass of solute=550g

therefore 110×100/550=20%

hope u will understand .:") credit to the owner

7 0
4 years ago
Stars can be classified into groups based on their
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4 years ago
During an experiment, 104 grams of calcium carbonate reacted with an excess amount of hydrochloric acid. If the percent yield of
postnew [5]

Answer:

92.4 grams.

Explanation:

  • From the balanced reaction:

<em>CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O,</em>

1.0 mole of CaCO₃ reacts with 2.0 moles of HCl to produce 1.0 mole of CaCl₂, 1.0 mole of CO₂, and 1.0 mole of H₂O.

  • We need to calculate the no. of moles of (104 g) of CaCO₃:

<em>no. of moles of CaCO₃ = mass/molar mass</em> = (104 g)/(100.08 g/mol) = <em>1.039 mol.</em>

<u><em>Using cross multiplication:</em></u>

1.0 mole of CaCO₃ produce → 1.0 mole of CaCl₂.

∴ 1.039 mole of CaCO₃ produce → 1.039 mole of CaCl₂.

∴ The amount of CaCl₂ produced = no. of moles x molar mass = (1.039 mol)(110.98 g/mol) = 114.3 g.

∵ percent yield of the reaction = [(actual yield)/(theoretical yield)] x 100.

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7 0
3 years ago
If 0.5 moles of CaO is mixed into 2 liters of solution, what is the molarity? Group of answer choices 0.25 moles / liter 4 moles
Vsevolod [243]

Answer:

The correct answer is 0.25 moles/liter

Explanation:

Molarity is a measure of concentration and is defined as the moles of solute in 1 liter of solution.

2 L solution-----0,5 moles of CaO

1 L solution -----x= (1 L solutionx0,5 moles of CaO)/2 L solution =

<em>x=0, 25 moles of Cao ---> 0,25M</em>

8 0
4 years ago
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