Answer:
20%
Explanation:
mass by mass percentage of a solution =(mass of solute)/(mass of solution)
mass of solute=550g
therefore 110×100/550=20%
hope u will understand .:") credit to the owner
It could be both A. and B. but most likely B. because the star can b big but have the same temperature as a smaller star.
Answer:
92.4 grams.
Explanation:
- From the balanced reaction:
<em>CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O,</em>
1.0 mole of CaCO₃ reacts with 2.0 moles of HCl to produce 1.0 mole of CaCl₂, 1.0 mole of CO₂, and 1.0 mole of H₂O.
- We need to calculate the no. of moles of (104 g) of CaCO₃:
<em>no. of moles of CaCO₃ = mass/molar mass</em> = (104 g)/(100.08 g/mol) = <em>1.039 mol.</em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of CaCO₃ produce → 1.0 mole of CaCl₂.
∴ 1.039 mole of CaCO₃ produce → 1.039 mole of CaCl₂.
∴ The amount of CaCl₂ produced = no. of moles x molar mass = (1.039 mol)(110.98 g/mol) = 114.3 g.
∵ percent yield of the reaction = [(actual yield)/(theoretical yield)] x 100.
Percent yield of the reaction = 80.15%, theoretical yield = 115.3 g.
<em>∴ actual yield = [(percent yield of the reaction)(theoretical yield)]/100 </em>= [(80.15%)/(115.3 g)] / 100 = <em>92.42 g ≅ 92.4 g.</em>
Answer:
The correct answer is 0.25 moles/liter
Explanation:
Molarity is a measure of concentration and is defined as the moles of solute in 1 liter of solution.
2 L solution-----0,5 moles of CaO
1 L solution -----x= (1 L solutionx0,5 moles of CaO)/2 L solution =
<em>x=0, 25 moles of Cao ---> 0,25M</em>