All categories

3 years ago

Find the perimeter & area of the rectangle. 2x-3 5(x-2)

Mathematics

1 answer:

shtirl [24]3 years ago

4 0

Step-by-step explanation:

The perimeter of a rectange is :

P = 2(L+B)

L is length and B is breadth

L = 2x-3 and B = 5(x-2)

⇒P = 2(L+B)

P = 2[2x-3+5(x-2)]

P = 2[2x-3+5x-10]

P = 2[7x-13]

The area of a rectangle is :

A = L×B

$A=(2x-3)\times 5(x-2)\\\\A=(2x-3)\times(5x-10)\\\\A=10x^2-10x-15x+30\\\\A=10x^2-25x+30$

You might be interested in

You are a supervisor for a home cleaning business,

irinina [24]

Answer:

option a

Step-by-step explanation:

i think this because my teacher in my business class stated this before to the whole class but I was distracted so it can totally be wrong if it is my bad

8 0

2 years ago

Identify the scale factor.

Xelga [282]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

32 - 5x is greater than or equal to 7 - 5(x - 5)

Damm [24]

Answer:

True 32≥32

Step-by-step explanation:

32-5x≥7-5(x-5)

32-5x≥7-5x+25

32-5x≥32-5x

+5x +5x

32≥32

6 0

3 years ago

An ellipse has a vertex at (4,0), a co-vertex at (0,3), and a center at the origin. Which is the equation of the ellipse in stan

bekas [8.4K]

ANSWER

$\frac{ {x}^{2} }{ 16} + \frac{ {y}^{2} }{ 9} = 1$

EXPLANATION

The given ellipse has a vertex at (4,0), a co-vertex at (0,3), and a center at the origin.

The equation of an ellipse with vertices on the x-axis and center at the origin is:

$\frac{ {x}^{2} }{ {a}^{2} } + \frac{ {y}^{2} }{ {b}^{2} } = 1$

The ellipse has vertex at (4,0) , hence a=4.

Also the co-vertex is at (0,3) , b=3

We substitute the values into the equation to get:

$\frac{ {x}^{2} }{ {4}^{2} } + \frac{ {y}^{2} }{ {3}^{2} } = 1$

$\frac{ {x}^{2} }{ 16} + \frac{ {y}^{2} }{ 9} = 1$

6 0

3 years ago

Please help my by today, I will give brainliest when I can :)

Murljashka [212]

Blonde and 7 hope this helps :))

8 0

2 years ago

Read 2 more answers