Let f be the function with variable n, which gives the number of pictures left in the phone after deleting pictures for n-days.
So f(1) gives the number of photos left after 1 day of deleting photos
f(2) gives the number of photos left after 2 days of deleting photos
and so on.
f(1)=745-20
f(2)=745-20-20=745-20*2
f(3)=745-20-20-20=745-20*3
so clearly f(n)=745-20n
Answer:
the algebraic expression is f(n)=745-20n,
where n is the n'th day of deleting photos, and f is the number of photos left after n days of deleting.
<h2>
Answer: x = 6</h2>
* = things that have changed or are being changed
<h2>
Explanation:</h2>
1. rearrange terms
*4
4 + 3
* = 5
+ 2
+ 2
0
*3x + 44* = 5x + 2 + 20
2. combine like terms
3 + 44 = *5x + 2* + 20
3 + 44 = *7x* + 20
3. Subtract 4
4 from both sides of the equation
3x + 44 = 7x + 20
3x + 44 *-44* = 7x + 20 *-44*
4. Simplify
(Subtract the numbers)
3x + *44 - 44* = 7x + 20 - 44
3x = 7x + 20 - 44
(Again)
3x = 7x + 20 *- 44*
3x = 7x - 24
5. Subtract 7
from both sides of the equation
3x = 7x - 24
3x *- 7x* = 7x - 24 *- 7x*
6. Combine like terms
*3x - 7x* = 7x - 24 - 7x
*-4x* = 7x - 24 - 7x
(Again)
-4x = *7x* - 24 *- 7x*
-4x = - 24
7. Divide both sides of the equation by the same term
-4x = - 24

8. Simplify
(Cancel terms that are in both the numerator and denominator)

*x* = 
(Divide the numbers)
x = 
x = 6
Go to the x and y and find the numbers between them and mark them...tell me if this is confusing or not
Answer:
a= 6, b= 3, c=pi
Step-by-step explanation:
2020 egdenuity just took the test