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Fynjy0 [20]
3 years ago
11

Which is true about the completely simplified difference of the polynomials 6x6 − x3y4 − 5xy5 and 4x5y + 2x3y4 + 5xy5?

Mathematics
2 answers:
Galina-37 [17]3 years ago
8 0
<span>Let be A= 6x6 − x3y4 − 5xy5 and B= 4x5y + 2x3y4 + 5xy5 and when we do their difference, it is A - B = 6x6 − x3y4 − 5xy5 -( 4x5y + 2x3y4 + 5xy5)=6x6 − x3y4 − 5xy5 - 4x5y - 2x3y4 - 5xy5 = 6x6 - x3y4 - 2x3y4 - 5xy5 -4xy5 -5xy5=6x6 - 3x3y4 -14xy5, so the final solution is A - B =6x6 - 3x3y4 -14xy5, the degree of this is equal to the degree of - 3x3y4, and it is 3+4=7, the answer is The difference has 3 terms and a degree of 7.</span>
sasho [114]3 years ago
3 0

Actually the correct answer is The difference has 4 terms and a degree of 7.Ii just taken a pre test over this.

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In a metal fabrication​ process, metal rods are produced to a specified target length of 15 feet. Suppose that the lengths are n
Leto [7]

Answer:

95% Confidence interval: (14.4537 ,15.1463)

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 feet

Sample mean, \bar{x} = 14.8 feet

Sample size, n = 16

Alpha, α = 0.05

Sample standard deviation, σ = 0.65 feet

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95% Confidence interval:

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 15 and}~\alpha_{0.05} = \pm 2.1314  

14.8 \pm 2.1314(\dfrac{0.65}{\sqrt{16}} ) \\\\= 14.8 \pm 0.3463 = (14.4537 ,15.1463)  

is the required confidence interval for the true mean length of rods.

3 0
3 years ago
Read 2 more answers
What is the measure of BC?
CaHeK987 [17]

Answer:

Measure of BC = 10.

Step-by-step explanation:

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3 0
3 years ago
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bixtya [17]

Answer:

Step-by-step explanation:

Answer:

=> 1/4  * \pi r^{2}

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<h2>Please mark my answer as the brainliest for further answers :)</h2>
4 0
3 years ago
2 / 5 + ? / 15 = 16 / 15
maksim [4K]

Answer:

65

Step-by-step explanation:

I dont know the answer hope this helps

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