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Tasya [4]
4 years ago
12

Martin is buying 400 video games for his entertainment store it's video game cost $20 which of the following could be used to fi

nd the total amount he will pay for the video games .​
Mathematics
1 answer:
stepan [7]4 years ago
4 0

Answer:

What are the following??

Step-by-step explanation:

Imma try to help tho

soo like 20$ per game and like 400 games

thats 20$*400=8,000 dollars

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Which of the following functions is graphed below?
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Hmmm I think either D or C
6 0
3 years ago
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you sold brownies for $3 each.You sold 14 more this week than last week altogether. You made $84. how many brownies did you sell
Luba_88 [7]

Answer: 8

Step-by-step explanation: Altogether you sold x last week, if you do x + 14 which is 2x12 brownies sold, then at 3$ each 3(2x+12)=84 so 6x + 36 = 84

84- 36 = 48/6 = 8

7 0
3 years ago
A survey of 700 adults from a certain region​ asked, "What do you buy from your mobile​ device?" The results indicated that 59​%
Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are  (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes n_{1} = 400 and n_{2} = 300

Proportion of mean p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52

<u>Null hypothesis H0</u> : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

<u>Alternative hypothesis H1:</u>- p1 ≠ p2

a) The test statistic is

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }

where p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}  

on calculation we get   p = 0.56    

now q =1-p = 1-0.56=0.44

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }\\   =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300}   }

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

<u>conclusion</u>:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) <u>95% confidence intervals</u>

The confidence intervals are P± 1.96(√PQ/n)

we know that = p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of <u>confidence intervals  (0.523 ,0.596)</u>

<u></u>

3 0
3 years ago
22
mina [271]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
Pic included Please answer!!!
TiliK225 [7]
The answer is -4 + 7. Because its subtracting 4 to zero which makes it -4. And then its adding 7 so the answer is -4+7
4 0
4 years ago
Read 2 more answers
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