O SYSTEMS OF EQUATIONS AND MATRICES
1 answer:
You might be interested in
༺༻
Total amount = $520
Sharing Ratio = 2 : 4 : 7
First Student Ratio : 2
Second Student Ratio : 4
Third Student Ratio : 7
Total Quantities of ratio = 2 + 4 + 7 = 13
<u>Formula</u><u> </u><u>applied</u><u> </u><u>:</u><u> </u>
Share = Ratio of Student / Total quantities of ratio × Total amount
First Student share :
= 2/13 × 520
= $80
Second student share:
= 4/13 × 520
= $160
Third Student share :
= 7/13 × 520
= $280 .
Proof :
Total share = $520
( 80 + 160 + 280 )= $520
$520 = $520
The formula we need is this one: 
. Filling in accordingly, we have x+4(x+4+1)=x+1(x+1+11). Simplifying that we get (x+4)(x+5)=(x+1)(x+12). We will FOIL both sides to get 
. Combining like terms gives us this simplification: 0=4x-8. If we factor out the common 4, we have 0 = 4(x-2). By the Zero Product Property, eitheer 4=0 or x-2=0. Well obviously, 4 does not equal zero, so x-2 = 0, and x = 2.