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Igoryamba
3 years ago
5

I'm doing elimination in systems of equations how do I solve this?????? Help!!!

Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0
X-3y=-5
-(x+3y=1)
-------------
-6y=-6
y=1
x=-2

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Which expression has the largest coefficient. Will mark brainliest. Plz include explanation.
slamgirl [31]

Answer:

Expression 3

Step-by-step explanation:

State that a coefficient is a multiplicative factor, is a number in front of a variable, in some term of a polynomial.

The coefficients of the expression 3, for example, are 3, 7 and 24.

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Using quadratic formula to find the solution for<br><br><br> y=3x^3+8x-1
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I would answer about 1/3 cups
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3 years ago
CAN someone help with #4 please?
Masja [62]
The constant of proportionality is <em>4 .</em>

The equation is  [ <em>Height = (4) times (Days)</em> ] .

When the sunflower is 60cm tall,                60 = (4) times (Days).

Divide each side of the equation by 4:       <em>15  =  Days</em>
8 0
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Read 2 more answers
2. Calculate an expression for dy/dx and d2y/dx2 in terms of t if the parametric pair is given as tan(x) = e^at and e^y = 1 + e^
Ber [7]

I assume a is a constant. If tan(x) = exp(at) (where exp(x) means eˣ), then differentiating both sides with respect to t gives

sec²(x) dx/dt = a exp(at)

Recall that

sec²(x) = 1 + tan²(x)

Then we have

(1 + tan²(x)) dx/dt = a exp(at)

(1 + exp(2at)) dx/dt = a exp(at)

dx/dt = a exp(at) / (1 + exp(2at))

If exp(y) = 1 + exp(2at), then differentiating with respect to t yields

exp(y) dy/dt = 2a exp(2at)

(1 + exp(2at)) dy/dt = 2a exp(2at)

dy/dt = 2a exp(2at) / (1 + exp(2at))

By the chain rule,

dy/dx = dy/dt • dt/dx = (dy/dt) / (dx/dt)

Then the first derivative is

dy/dx = (2a exp(2at) / (1 + exp(2at))) / (a exp(at) / (1 + exp(2at))

dy/dx = (2a exp(2at)) / (a exp(at))

dy/dx = 2 exp(at)

Since dy/dx is a function of t, if we differentiate dy/dx with respect to x, we have to use the chain rule again. Suppose we write

dy/dx = f(t)

By the chain rule, the derivative is

d²y/dx² = df/dx

d²y/dx² = df/dt • dt/dx

d²y/dx² = (df/dt) / (dx/dt)

d²y/dx² = 2a exp(at) / (a exp(at) / (1 + exp(2at)))

d²y/dx² = 2 (1 + exp(2at))

4 0
2 years ago
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