Help i need this one question asap
2 answers:
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Answer:
The correct options are:
- g(x) is shifted three units higher than f(x).
- g(x) has a period that is half the period of f(x).
Step-by-step explanation:
We have to compare the graphs of the function:
and
We have to select the correct options among the following:
As we know that the period of sine function is 2π.
i.e. Period of function f(x) is: 2π.
The period of sin(2 x) is π.
Hence, the period of the function g(x) function is π.
- Hence, the period of g(x) is half the period of f(x).
- Also we could observe that g(x) is shifted 3 units upward.
Answer:
Step-by-step explanation:
Given function is,
Factors of the numerator = x² - 3x + 2
= x² - 2x - x + 2
= x(x - 2) - 1(x - 2)
= (x - 2)(x - 1)
Therefore, given function will be,
f(x) =
For (x - 2) = 0
For x = 2, denominator will become zero.
Thus for input value x = 2, function will not be defined.
If x ≠ 2, f(x) = x - 1
It's a linear function represented by f(x) = x - 1
Having slope = 1 and y-intercept = -1
And (2, 1) is a hole as shown in the graph.