A store manager pays $40 for a shirt and adds a markup

Find the area of the parrallelogram

Zolol [24]

Answer:

I believe it is about 47.63 meters squared

Leave a comment if you'd like a step-by-step explanation

5 0

3 years ago

Nate is watching a baseball game. So far, 15 batters have gotten a hit and 5 batters have not. Out of the next 4 batters, how ma

iren2701 [21]

Answer:

3 batters

Step-by-step explanation:

For the past data, we have observed that:

15 batters have gotten a hit

5 batters have not

The total of batters that we have observed is

n = 15 + 5 = 20

Therefore, this means that based on the observed data, the probability that a batter gets a hit is:

$p(hit)=\frac{n(h)}{n}=\frac{15}{20}=0.75$

where

n(h) = 15 is the number of batters that got a hit

After that, we want to know how many batters we will expect to get a hit in the next 4 batters. We can write it as:

$n(h) = 4 \cdot p(hit)$

And since

p(hit) = 0.75

We find:

$n(h)=4\cdot 0.75 =3$

So, we expect 3 batters to get a hit in the next 4.

7 0

3 years ago

Juan received a $45.25 gift card for a photo center. He used it to buy prints that cost 25 cents each. The remaining balance, B

Bas_tet [7]

Answer:

37.75

Step-by-step explanation:

0.25 x 30 = 7.5

45.25 - 7.5 = 37.75

4 0

3 years ago

A tank contains 60 lb of salt dissolved in 400 gallons of water. A brine solution is pumped into the tank at a rate of 4 gal/min

Natali5045456 [20]

The complete question is;

A tank contains 60 lb of salt dissolved in 400 gallons of water. A brine solution is pumped into the tank at a rate of 4 gal/min; it mixes with the solution there, and then the mixture is pumped out at a rate of 4 gal/min. Determine the amount of salt in the tank at any time

t, if the concentration in the inflow is variable and given by

c(t) = 2 + sin(t/4) lb/gal.

Answer:

dA/dt = (8 + 4sin(t/4)) - (A_t/100)

Step-by-step explanation:

Rate is given as;

dA/dt = R_in - R_out

R_in = (concentration of salt inflow) x (input rate of brine)

So, R_in = (2 + sin(t/4)) x 4 = (8 + 4sin(t/4))

The solution is being pumped out at the same rate, thus it is accumulating at the same rate.

After t minutes, there will be 400 + (0 x t) gallons left = 400 gallons left

Thus,

R_out =(concentration of salt outflow) x (output rate of brine)

R_out = (A_t/400) x 4 = A_t/100

Thus,

A_t = (100/t)(8t - 16cos(t/4) - 60)

Since we want to find the amount of salt, A(t), let's integrate;

Thus, A = 8t - 16cos(t/4) - (A_t/100)t

A = 60 from the question. Thus,

60 = 8t - 16cos(t/4) - (A_t/100)t

Let's try to make A_t the subject;

(A_t/100)t = 8t - 16cos(t/4) - 60

A_t = (100/t)(8t - 16cos(t/4) - 60)

3 0

3 years ago

.Write the quadrants/axes in which the following points lie a) (2,-3) b)(0,8) c)(-1,-2) d)(4,7)

natka813 [3]

Answer:

[see below]

Step-by-step explanation:

Quadrant One has a positive value for both x and y. (+ , +)

Quadrant Two has a negative x value. (- , +)

Quadrant Three has a negative value for both x and y. (- , -)

Quadrant Four has a negative y value. (+, -)

Therefore:

(2, -3) would be plotted in Q4. It does not lie on any axis.

(0, 8) would be on the positive y-axis. (0 is neither negative nor positive.)

(-1, -2) would be plotted in Q3. It does not lie on any axis.

(4, 7) would be plotted in Q1. It does not lie on any axis.

5 0

3 years ago