Question

Someone help me with this. I forgot my notes in class

Answer 1

Step-by-step explanation:

$In\: \triangle ABC\\\\BA = BC... (Given) \\\\\therefore \angle BAC = \angle BCA \\(Angles \:opposite\: to \:equal\:\\sides\:are\: equal) \\\\\because m\angle BCA= 8x... (Given) \\\\\therefore \angle BAC = 8x\\\\In\: \triangle ABC\\\\m\angle ABC + m\angle BAC + m\angle BCA \\= 180\degree \\\\\therefore \: 44x + 8x + 8x = 180\degree \\\\\therefore \: 60x= 180\degree \\\\\therefore \: x= \frac{180\degree}{60} \\\\\therefore \: x= 3\degree\\\\\therefore \: m\angle B =44x = 44\times 3\degree\\\\\therefore \: m\angle B =132\degree\\\\m\angle A= m\angle C=8x =8 \times 3\degree\\\\\therefore \: m\angle A= m\angle C= =24\degree$

Answer 2

Answer:

see explanation

Step-by-step explanation:

Since AB = BC the the triangle is isosceles and thus

∠ A = ∠ C = 8x

The sum of the 3 angles in a triangle = 180°

Sum the 3 angles and equate to 180

44x + 8x + 8x = 180, that is

60x = 180 ( divide both sides by 60 )

x = 3

Thus

∠ A = ∠ C = 8x = 8(3) = 24°

∠ B = 44x = 44(3) = 132°