All categories

4 years ago

Change the following equation to slope, intercept form 3x-y=5. show your work

Mathematics

2 answers:

Semmy [17]4 years ago

7 0

^^^^ what he/she did seem ably right!

Paladinen [302]4 years ago

6 0

Answer:

y = -3x -5

Step-by-step explanation:

First subtract 3x from both sides

-y = 3x + 5

Then divide the - (1) from both sides

y = -3x - 5

You might be interested in

Pls help best answer will get brainiest

agasfer [191]

Answer:

Point A and point B have 11 units between

Step-by-step explanation:

If the distance between 0 and 10 is 10 also known as the absolute value, you just add one more unit because it starts at -1

So 10 + 1 = 11 and because we are using 10 is greater than 1 its positive so the answer is 11

Hope this helps :)

8 0

3 years ago

Which pair of numbers have a GCF of 2? Choose all answers that are correct. A. 10 and 2 B. 4 and 6 C. 6 and 12 D. 2 and 24

il63 [147K]

A.
GCF(10; 2) = 2 /factors of 10: 1, 2, 5, 10; factors of 2: 1, 2/

B.
GCF(4; 6) = 2 /factors of 4: 1, 2, 4; factors of 6: 1, 2, 3, 6/

C.
GCF(6; 12) = 6 /factors of 6: 1, 2, 3, 6; factors of 12: 1, 2, 3, 4, 6, 12/

D.
GCF(2; 24) = 2 /factors of 2: 1, 2; factors of 24: 1, 2, 3, 4, 6, 8, 12, 24/

Answer: A, B and D.

8 0

3 years ago

Read 2 more answers

Pls answer correctly and I’ll mark you as brainly

ch4aika [34]

2g/18 because if g=3, then 1-2/3=1/3, and 6/18=1/3

7 0

3 years ago

System of equations help

Ipatiy [6.2K]

Answer:

Step-by-step explanation:

trust me

5 0

3 years ago

A teacher categorized students by whether they regularly completed their homework (or not) and whether they passed the course (o

ella [17]

Probabilities are used to determine the chances of an event.

Let P represents the event that a student passes the course, and C represents the event that a student completes the assignment

(a) The probability a student passed the course given that they completed their homework?

From the table, we have:

$\mathbf{n(P\ n\ C) = 25}$

$\mathbf{n(C) = 30}$

So, the required probability is:

$\mathbf{Pr = \frac{n(P\ n\ C)}{n(C)}}$

This gives

$\mathbf{Pr = \frac{25}{30}}$

$\mathbf{Pr = 0.8333}$

Express as percentage

$\mathbf{Pr = 83.33\%}$

Hence, the probability a student passed the course given that they completed their homework is 83.33%

(b) The probability a student passed the course given that they didn't complete their homework

From the table, we have:

$\mathbf{n(P\ n\ C'= 7}$

$\mathbf{n(C') = 25}$

So, the required probability is:

$\mathbf{Pr = \frac{n(P\ n\ C')}{n(C')}}$

This gives

$\mathbf{Pr = \frac{7}{25}}$

$\mathbf{Pr = 0.28}$

Express as percentage

$\mathbf{Pr = 28\%}$

Hence, the probability a student passed the course given that they didn't complete their homework is 28%

(c) The probability a student completed their homework given that passed the course?

From the table, we have:

$\mathbf{n(P\ n\ C) = 25}$

$\mathbf{n(P) = 32}$

So, the required probability is:

$\mathbf{Pr = \frac{n(P\ n\ C)}{n(P)}}$

This gives

$\mathbf{Pr = \frac{25}{32}}$

$\mathbf{Pr = 0.78125}$

Express as percentage

$\mathbf{Pr = 78.125\%}$

Approximate

$\mathbf{Pr = 78.13\%}$

Hence, the probability a student completed their homework given that they passed the course is 78.13%

(d) The probability a student didn't complete their homework given that they didn't pass the course

From the table, we have:

$\mathbf{n(P'\ n\ C'= 18}$

$\mathbf{n(P) = 23}$

So, the required probability is:

$\mathbf{Pr = \frac{n(P'\ n\ C')}{n(P')}}$

This gives

$\mathbf{Pr = \frac{18}{23}}$

$\mathbf{Pr = 0.7826}$

Express as percentage

$\mathbf{Pr = 78.26\%}$

Hence, the probability a student didn't complete their homework given that they didn't pass the course is 78.26%

Change the following equation to slope, intercept form 3x-y=5. show your work​

Change the following equation to slope, intercept form 3x-y=5. show your work