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3 years ago

13

Graham's monthly bank statement showed the following deposits and withdrawals.

1 answer:

pychu [463]3 years ago

8 0

Answer:

622.27

Step-by-step explanation:

- $87.45 + (- $24.76) + (-17.29) = $-129.5

$143.87 + $348.90 = $492.77

492.77 - (-129.5) = 622.27

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OleMash [197]

1/2 im pretty sure im right

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4 years ago

Use the graph below to answer this question:

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3 years ago

Read 2 more answers

5 and 2/3 divided by 4?

Nikolay [14]

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3 years ago

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Lieutenant Commander Data is planning to make his monthly (every 30 days) trek to Gamma Hydra City to pick up a supply of isolin

Nookie1986 [14]

Answer:

a

$N = 209 \ unites$

b

$N_{max} = 249$

Step-by-step explanation:

From the question we are told that

The daily demand is $d = 7/day$

The standard deviation is $\sigma = 3 /day$

The service probability is $s = 95\% = 0.95$

The number of chips in the inventory is $k = 40$

The number of days in his monthly is $T = 30 \ days$

The lead time is $L = 4$

Generally the number he should order (optimal order ) is mathematically represented as

$N = d(L + T)+(\sigma_{T + L} * z) -k$

Here $\sigma__{T+L }}$ is the monthly standard deviation which is mathematically evaluated as

$\sigma__{T + L}} = \sqrt{(T + L) * 1^2}$

=> $\sigma__{T + L}} = \sqrt{34}$

=> $\sigma__{T+L}} = 5.83$

Also z-value for the 95% service probability from the z-table is 1.96

So

$N = 7 * (30 +4 ) + (1.96 * 5.83) - 40$

=> $N = 209 \ unites$

For the maximum order quantity k = 0

So

$N_{max} = d(L + T)+(\sigma_{T + L} * z) -0$

=> $N_{max} = 7 * (30 +4 ) + (1.96 * 5.83) - 0$

=> $N_{max} = 249$

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3 years ago

Systems of Equations

daser333 [38]

Answer:

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Step-by-step explanation:

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