Given:
Sides of triangles in the options.
To find:
Which could NOT be the lengths of the sides of a triangle.
Solution:
Condition for triangle:
Sum of two smaller sides of a triangle must be greater than the longest side.
In option A,

Sides 5 in, 5 in, 5 in are the lengths of the sides of a triangle.
In option B,

Sides 10 cm, 15 cm, 20 cm are the lengths of the sides of a triangle.
In option C,

Sides 3 in, 4 in, 5 in are the lengths of the sides of a triangle.
In option D,

Since, the sum of two smaller sides is less than the longest side, therefore the sides 8 ft, 15 ft, 5 ft are not the lengths of the sides of a triangle.
Therefore, the correct option is D.
Answer:
The answer is V = π r 2h
Trust me i just got this question and that was the answer.
Step-by-step explanation:
1. You are given PR and RS, so simply add the two measurements to get PS.
28.2+30.7= 58.9
2. Subtract QV from QT to get TV.
78-56= 22
3. Again, Subtract QV from QT to get TV.
74-36= 38
4. Similar to question 1, add PR and RS to get PS.
40+53= 93
Calculating surface area
Big Prism-
7*14*2=196
7*21*2=294
14*21*2=588
196+294+588=1078
Small prism
3*6*2=36
3*9*2=54
6*9*2=108
36+54+108=198
1078:198
Simplify(divide by common factors)
(Divide2)
539:99
(Divide 11)
49:9
C is your answer
Well
the
terms
are
not
given
below
so
i
cant
help
you
sorry