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Zolol [24]
2 years ago
11

Can someone help me with this Q :)

Mathematics
2 answers:
mihalych1998 [28]2 years ago
8 0

Answer:

its the digram: )

Step-by-step explanation:

yawa3891 [41]2 years ago
8 0

Answer:

*888888888877727723772289292

Step-by-step explanation:

88ejei49 + 710 is 49 + 710 is 10390..49 + 710 is 10390.

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So in the photo, I was trying to do an order of operations problem with photomath. But I don’t like to cheat without understandi
nordsb [41]

Answer:

the answer of the complete equation is 0

Step-by-step explanation:

first you multiply by 2 all in the parenthesis, 2(15) and 2(3) you got a 30. Then you do the exponents 3(3) is 9

so you got like this= 30-6+9(4)

You multiply 9 and 4=

30-6+36

and the answer is 0

3 0
3 years ago
Can you name the angle pairs and type the correct code? Please remember to type in ALL CAPS with no spaces.
Anarel [89]
JEANNNNNNMNNNNNNNNNNNNNN

4 0
2 years ago
Prove: cot(x) sec^4(x) = cot(x) +2tan(x) + tan^3(x)
masha68 [24]
\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad\qquad 
sec(\theta)=\cfrac{1}{cos(\theta)}\quad\qquad  1+tan^2(\theta)=sec^2(\theta)\\\\\\
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}
\qquad \qquad cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\\\\
-------------------------------\\\\
cot(x)sec^4(x)=cot(x)+2tan(x)+tan^3(x)\\\\
-------------------------------\\\\

\bf \textit{so, let's do the left-hand-side}\\\\
cot(x)sec^2(x)sec^2(x)\implies cot(x)[1+tan^2(x)][1+tan^2(x)]
\\\\\\
cot(x)[1^2+2tan^2(x)+tan^4(x)]
\\\\\\
cot(x)+2tan^2(x)cot(x)+tan^4(x)cot(x)
\\\\\\
cot(x)+2\cdot \cfrac{sin^2(x)}{cos^2(x)}\cdot \cfrac{cos(x)}{sin(x)}+\cfrac{sin^4(x)}{cos^4(x)}\cdot \cfrac{cos(x)}{sin(x)}
\\\\\\
cot(x)+2\cdot \cfrac{sin(x)}{cos(x)}+\cfrac{sin^3(x)}{cos^3(x)}\implies \boxed{cot(x)+2tan(x)+tan^3(x)}
8 0
3 years ago
A)x 1/9
STALIN [3.7K]

Answer:

Answer should be x^9

Step-by-step explanation:

This equation looks really complicted, but it's actually much easier when you break it down! First, your going to multiply the fraction 3/2 by 6 - since one is a fraction, youre going to find the GCF, or Greatest Common Factor, and reduce it. The GCF in this equation is 2, so we eliminate the two from the fraction (making it just 3) and divide 6 by 2 (getting 3). Thus, we are left with (x^3)^3 -> 3 x 3 = 9. So we are left with x^9. I hope this helps!

5 0
3 years ago
A parallelogram is ______ a rhombus. never, always, sometimes​
Nataly [62]

Answer:

never

Step-by-step explanation:

5 0
3 years ago
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