Let's say that the unknown value here is c. Although we are given two points on the line, it is only necessary to use one as there is only one unknown value, so let's say we choose the point (6, -12) and substitute this into the equation:
-12 = 1(6) - c
-12 - 6 = -c
-18 = -c
c = 18
Thus the equation for the line is y = 1x - 18
The lost pair of weight can be found by subtracting the a known pair from
the total weight leaving the value of the lost pair.
<u>The lost weight of a pair of boys is 120 kg</u>
Reasons:
Let <em>a</em>, <em>b</em>, <em>c</em>, and <em>d</em><em> </em>represent the weights of the four boys, we have;
The number of ways of selecting pairs (two boys) of boys from a group of
four is given using combination formula as follows;

Which gives;

₄C₂ = 6
Therefore, the weights of the pairs are;
a + b = 110
a + c = 112
a + d = 113
b + c = 118
b + d = 121
c + d = Lost weight
a + b + c + d = 230 (given)
Therefore;
The lost weight, c + d = 230 - (a + b)
Which gives;
c + d = 230 - (110) = 120
The lost weight = c + d = 120
- <u>The lost weight = 120 kg</u>
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brainly.com/question/12974932
A) The signs of the first derivative (g') tell you the graph increases as you go left from x=4 and as you go right from x=-2. Since g(4) < g(-2), one absolute extreme is (4, g(4)) = (4, 1).
The sign of the first derivative changes at x=0, at which point the slope is undefined (the curve is vertical). The curve approaches +∞ at x=0 both from the left and from the right, so the other absolute extreme is (0, +∞).
b) The second derivative (g'') changes sign at x=2, so there is a point of inflection there.
c) There is a vertical asymptote at x=0 and a flat spot at x=2. The curve goes through the points (-2, 5) and (4, 1), is increasing to the left of x=0 and non-increasing to the right of x=0. The curve is concave upward on [-2, 0) and (0, 2) and concave downward on (2, 4]. A possible graph is shown, along with the first and second derivatives.