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Studentka2010 [4]
3 years ago
5

10 POINTS!!! FULL ANSWER IN STEP BY STEP FORMAT!!

Mathematics
1 answer:
stich3 [128]3 years ago
8 0
A) The signs of the first derivative (g') tell you the graph increases as you go left from x=4 and as you go right from x=-2. Since g(4) < g(-2), one absolute extreme is (4, g(4)) = (4, 1).

The sign of the first derivative changes at x=0, at which point the slope is undefined (the curve is vertical). The curve approaches +∞ at x=0 both from the left and from the right, so the other absolute extreme is (0, +∞).

b) The second derivative (g'') changes sign at x=2, so there is a point of inflection there.

c) There is a vertical asymptote at x=0 and a flat spot at x=2. The curve goes through the points (-2, 5) and (4, 1), is increasing to the left of x=0 and non-increasing to the right of x=0. The curve is concave upward on [-2, 0) and (0, 2) and concave downward on (2, 4]. A possible graph is shown, along with the first and second derivatives.

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Find the volume of the square pyramid below.
miv72 [106K]

Hello!

\bf ANSWER

The volume of the square pyramid is approximately \boxed{ \bf 19.19~km^3}

____________________________________________________________

\bf EXPLANATION

V = a^{2}\frac{h}{3}

First, we must find the area of the square base.

A = l * w

A = 3.5 * 3.5

A = 12.25 km^2

The area of the base is 12.25 km^2. Now, multiply the base area by the perpendicular height. Then divide by 3.

V = (12.25 * 4.7) / 3

V = 19.1916666667

V ≈ 19.19 km^3



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