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crimeas [40]
2 years ago
15

Four boys weighed themselves in different pairs and alone. The weights of the pairs were 110 kg, 112 kg, 113 kg, 118 kg, 121 kg,

and the weight of one pair was lost. The total weight of the four boys was 230 kg. What was the lost weight?
Mathematics
2 answers:
brilliants [131]2 years ago
6 0

The lost pair of weight can be found by subtracting the a known pair from

the total weight leaving the value of the lost pair.

<u>The lost weight of a pair of boys is 120 kg</u>

Reasons:

Let <em>a</em>, <em>b</em>, <em>c</em>, and <em>d</em><em> </em>represent the weights of the four boys, we have;

The number of ways of selecting pairs (two boys) of boys from a group of

four is given using combination formula as follows;

_nC_r = \dfrac{n!}{r! \cdot (n - r)!}

Which gives;

_4C_2 = \dfrac{4!}{2! \cdot (4 - 2)!} = 6

₄C₂ = 6

Therefore, the weights of the pairs are;

a + b = 110

a + c = 112

a + d = 113

b + c = 118

b + d = 121

c + d = Lost weight

  • c + d = Lost weight

a + b + c + d = 230 (given)

Therefore;

The lost weight, c + d = 230 - (a + b)

Which gives;

c + d = 230 - (110) = 120

The lost weight = c + d = 120

  • <u>The lost weight = 120 kg</u>

Learn more here:

brainly.com/question/12974932

mina [271]2 years ago
6 0

Answer:

116

Step-by-step explanation:

you can use variables

a+b=110

a+c=112

a+d=113

b+c=118

b+d=121

add up the weights and you get 574 kg (you need to find c+d)

3a+3b+2c+2d=574

a+b+c+d = 230 as given then you multiply by 3 so you can cancel out 3a and 3b and subtract 690-574 because we multiplied by 3

you are left with c+d=116

similar method to the answer previously

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