The solution of a system of two linear equations yields the equation 0=3. Describe what the graph of the system looks like.

denis-greek [22]

Answer:

$\frac{7}{10} |$

Step-by-step explanation:

STEP 1:

2/3 + 7/10 = ?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(2/3, 7/10) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

$(\frac{2}{3}$ * $\frac{10}{10})$ + $(\frac{7}{10} * \frac{3}{3})$ = ?

Complete the multiplication and the equation becomes

$\frac{20}{30} + \frac{21}{30}$

The two fractions now have like denominators so you can add the numerators.

Then:

$\frac{20+21}{30} = \frac{41}{30}$

This fraction cannot be reduced.

The fraction 41/30

is the same as

41 divided by 30

Convert to a mixed number using

long division for 41 ÷ 30 = 1R11, so

41/30 = 1 11/30

Therefore:

2/3+7/10= 1 11/30

STEP 2:

41/30 + -2/3

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(41/30, -2/3) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

$(\frac{41}{30} *\frac{1}{1} ) + ( \frac{-2}{3} * \frac{10}{10} )$

The two fractions now have like denominators so you can add the numerators.

Then:

$\frac{41+-20}{30} = \frac{21}{30}$

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 21 and 30 using

GCF(21,30) = 3

$\frac{21/3}{30/3} =\frac{7}{10}$

Therefore:

$\frac{41}{30} + \frac{-2}{3} =\frac{7}{10}$ |

8 0

3 years ago

Adam is three years older than Joe. After three years, Adam's age will be four years less than two times Joe's age. Considering

Romashka-Z-Leto [24]

Answer:

X = 3+y

X = 2y - 4

Step-by-step explanation:

3 0

3 years ago

A package of 10 batteries is checked to determine if there are any dead batteries. Four batteries are checked. If one or more ar

frutty [35]

Answer:

There is a probability of 76% of not selling the package if there are actually three dead batteries in the package.

Step-by-step explanation:

With a 10-units package of batteries with 3 dead batteries, the sampling can be modeled as a binomial random variable with:

n=4 (the amount of batteries picked for the sample).
p=3/10=0.3 (the proportion of dead batteries).
k≥1 (the amount of dead batteries in the sample needed to not sell the package).

The probability of having k dead batteries in the sample is:

$P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}$

Then, the probability of having one or more dead batteries in the sample (k≥1) is:

$P(x\geq1)=1-P(x=0)\\\\\\P(x=0) = \dbinom{4}{0} p^{0}q^{4}=1*1*0.7^4=0.2401\\\\\\P(x\geq1)=1-0.2401=0.7599\approx0.76$

8 0

3 years ago

PLEASE HELP I NEED HELP WITH THIS ASAP. PLEASE show work, thank you. Will give branliest

d1i1m1o1n [39]

If the slope is 5 perpendicular would be -1/5 just flip the slope around

3 0

3 years ago

A market analyst is hired to provide information on the type of customers who shop at a particular store. A random survey is tak

sveta [45]

Complete question:

A market analyst is hired to provide information on the type of customers who shop at a particular store. A random survey is taken of 100 shoppers at this store. Of these 100, 73 are women. The shoppers The data is summarized below. we grouped in three age categories, under 30, 30 up to 50 and 50 and over. Women under 30 are 30, Men under 30 are 8 Women 30 to 50 are 25 and Men are 14 Women 50 and over are 18 and Men are 5.

Let W be the event that a randomly selected shopper is a woman. Let A be the event that a randomly selected shopper is under 30. a.) Find the probability of W. W (women Shoppers) = Find the probability of A. b.) Find the probability of A and W. c.) P (A and W) (Shoppers) d.) Find the probability of A or W. P(A or W) (Shoppers) e.) Find the probability of A given W

Answer:

A) P(W) = 73/100; B) P(A) = 38/ 100 C) 30 / 100

D) 81/100 E) 30/73

Step-by-step explanation:

- - - - - - - - Women Men Total

Under 30 - - - 30 - - - 8 - - 38

30 to 50 - - - - 25 - - 14 - - 39

50 & over - - - 18 - - - 5 - - -23

Totals - - - - - - 73 - - -27 - - 100

Recall:

Probability : P= (required outcome / Total possible outcomes)

A) probability of women shoppers: P(W)

Number of women shoppers = 73; total shoppers = 100

P(W) = 73/100

B) Probability of under 30: P(A)

= number of shoppers under 30 = 38

Tital number of shoppers = 100

P(A) = 38/ 100

C) probability of A and W; This is the probability that the selected person is a woman and under 30.

(W n A) = 30

= 30 / 100

D) probability of A or W:

P(A) + P(W) - P(A n W) :

(38 / 100 + 73 / 100 - 30 / 100) = (38+73-30) /100

= 81/100

E) probability of A given W:

P(A n W) / P(W) = 30/73

5 0

3 years ago