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____ [38]
2 years ago
9

What is the sum of the arithmetic sequence 3, 9, 15 if there are 34 terms?

Mathematics
1 answer:
Tanya [424]2 years ago
4 0
<h3>Answer:  3468</h3>

===================================================

Work Shown:

a = first term = 3

d = common difference = 6

S(n) = sum of the first n terms of an arithmetic sequence

S(n) = (n/2)*(2a + d(n-1))

S(34) = (34/2)*(2*3 + 6(34-1))

S(34) = 3468

--------

Check:

3+9+15+21+27+33+39+45+51+57+63+69+75+81+87+93+99+105+111+117+123+129+135+141+147+153+159+165+171+177+183+189+195+201 = 3468

I used GeoGebra to generate the 34 terms shown above. You could do so by hand (start at 3; add 6 to each term to get the next one), but it's a tedious busywork type of problem in my opinion. It's best left to computer software.

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3 years ago
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Irina-Kira [14]

Answer:

Therefore you will have to wait 11 minutes.

Step-by-step explanation:

Find the number of minutes between 5:00am and 8:37am

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Divide 217 by 12 to see how many bus stops have already been made

217/12=18

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Hope this helps!

8 0
3 years ago
PLEASE HELP ME WITH THXXXXXX:)))))))))
Fantom [35]
1) (-7,2)
y=2, -x+4=11, -x=11-4=7, x=-7

2) (-3,4)
-x+2y=11
y=4, -x+8=11, -x=3, x=-3

3) (1,6)
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4 0
3 years ago
Explain what the acronym PEMDAS means and how you use it when evaluating expressions.​
netineya [11]
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2 years ago
Decrease 1800 in the ratio 5:3​
oksano4ka [1.4K]

Answer:

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Step-by-step explanation:

a decrease in the ratio 5:3 implies that:

new quantity :old quantity :5:3

let new quantity be x.

x:1800=5:3

x/1800=5/3

3x=9000

x=9000/3

x=3000

8 0
2 years ago
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