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3 years ago

Multiply (a-b)(a^2+ab+b^2)

Mathematics

1 answer:

AlexFokin [52]3 years ago

3 0

Answer:

=(a-b)(a^2+ab+b^2)

= a^3+a^2b+ab+ab^2-ba^2-ab^2-b^3

SIMPLIFY

=a^3+ab-b^3

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Bridgette has $200 in a savings account that earns 10% annually. The interest is not compounded. How much interest will she earn

Pachacha [2.7K]

Answer:

$20

Step-by-step explanation:

10% = 10/100 = 0.1

So 10% of 200 = 200 x 0.1 = 20

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3 years ago

A rectangular garden has dimensions of 100 feet by 10 feet. Next season, the garden is decreased to 2/5 of its size. What is the

mina [271]

Answer:

40 feet by 4 feet

Step-by-step explanation:

Given length (l) = 100 feet

width (w) = 10 feet

As mentioned in the question the size of garden is decreased to 2/5 of its size. <u>It will effect the length and width with the same proportion.</u>

So,

New length = 100 * 2/5 = 40 feet

New width = 10 * 2/5 = 4 feet

Therefore, the scale of new drawing would be 40 feet by 4 feet

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4 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

miss Akunina [59]

Answer:

a. 0.343

b. 0.657

c. 0.189

d. 0.216

e. 0.353

Step-by-step explanation:

We use the combination formula of probability distribution to solve the question.

Where P(x=r) = nCr * p^r * q^n-r

Where n = number of trials = 3 vehicles

r = desired outcome of trial which varies.

p = probability of success = 70% =0.7

q = probability of failure = 1-p = 0.3

a. Probability that all 3 vehicles passed = P(X=3)

= 3C3 * 0.7^3 * 0.3^0 = 1 * 0.343 * 1

= 0.343.

b. Probability that at least one fails = 1 - (probability that none failed)

And probability that none failed = probability that all 3 vehicles passed.

Hence Probability that at least one fails = 1 - (probability that all 3 vehicles passe)

= 1 - 0.343

= 0.657

c.) probability that exactly one pass= P(X=1)

= 3C1 * 0.7¹ * 0.3² = 3 * 0.7 * 0.09

= 0.189

d.) probability that at most One of the vehicles passed = probability that none passed + probability of one passed.

Probability that none of the vehicles passed = P(X=0)

= 3C0 * 0.7^0 * 0.3^3 = 1*1*0.027

=0.027

Probability that one passed as calculated earlier = 0.189

Hence probability that at most one vehicle passed = 0.189 + 0.027 = 0.216

e.) Probability that all three Vehicles pass given that at least one pass = (probability of all three vehicles passes) / (probability that at least one passes)

Probability that at least one pass = 1 - probability that none passed.

= 1 - 0.027

= 0.973

Hence,

Probability that all three Vehicles passed given that at least one passed = 0.343/0.973

= 0.3525 = 0.353 (3.d.p)

7 0

3 years ago

If the point (x, -2) is a solution to the equation y = 2x – 4, find the value of x.

guapka [62]

This should your answer:

X = 4

7 0

3 years ago

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Rectangle divided into four rectangles. The perimeters of rectangle #1, #2, #3, #4 are 10 cm, 20 cm, 28 cm and 18 cm respectivel

notsponge [240]

Answer:

Perimeter of big rectangle = 38 units

Step-by-step explanation:

Let the sides of rectangle (1) = a and c cm

Sides of rectangle (2) = b and c cm

Sides of rectangle (3) = b and d cm

Sides of rectangle (4) = a and d cm

Perimeter of (1) = 2(length + width)

2(a + c) = 10

a + c = 5 ---------(1)

Perimeter of (2) = 2(b + c)

2(b + c) = 20

b + c = 10 -------(2)

Perimeter of (3) =2(b + d)

2(b + d) = 28

b + d = 14 --------(3)

Perimeter of (4) = 2(a + d)

2(a + d) = 18

a + d = 9 -------(4)

Since perimeter of the big rectangle = 2(a + b + c + d)

By adding equations (1) + (2) + (3) + (4),

(a + c) + (b + c) + (b + d) + (a + d) = 5 + 10 + 14 + 9

2(a + b + c + d) = 38

Therefore, perimeter of the rectangle ABCD = 38 units

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3 years ago

Multiply (a-b)(a^2+ab+b^2)​

Multiply (a-b)(a^2+ab+b^2)