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labwork [276]
3 years ago
10

Which expression is equivalent to this polynomial expression? (2x^5 + 3y^4)(-4x^2 + 9y^4)

Mathematics
1 answer:
kow [346]3 years ago
7 0

Answer:

18x5y4+27y8−8x7−12x2y4

Step-by-step explanation:

(2x5+3y4)(−4x2+9y4)

=(2x5)(−4x2)+(2x5)(9y4)+(3y4)(−4x2)+(3y4)(9y4)

=−8x7+18x5y4−12x2y4+27y8

=18x5y4+27y8−8x7−12x2y4

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The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis
Firdavs [7]

Answer:

sin\theta_1 =  - \frac{2\sqrt{70}}{19}

Step-by-step explanation:

We are given that \theta_1 is in <em>fourth</em> quadrant.

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Using \theta_1 in place of \theta:

sin^2\theta_1 + cos^2\theta_1 = 1

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\theta_1 is in <em>4th quadrant </em>so sin\theta_1 is negative.

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Answer:

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