Question

What is the equation of the line that passes through the points (-1, 3) and (1, 11)

Answer 1

Answer:

To find the slope of this line, you would use the formula

y2 - y1/ x2 - x1

11 - 3 / 1 - (-1)=

8/2

4

The slope of your line would be 4

Step-by-step explanation:

Answer 2

Equation of line passing through (-1 , 3) and ( 1 , 11 ) is y - 3= 4x + 4

Solution:

Need to determine equation of line passing through points ( -1 , 3 ) and ( 1 ,11 )    Equation of line passing through point $\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)$ is  given by  

$y-y_{1}=\frac{\left(y_{2}-y_{1}\right)}{\left(x_{2}-x_{1}\right)}\left(x-x_{1}\right)$   ---- equation 1

$\text { Here } x_{1}=-1, y_{1}=3, x_{2}=1, y_{2}=11$

Substituting given value in (1) we get

$\begin{array}{l}{y-3=\frac{(11-3)}{(1-(-1))}(x-(-1))} \\\\ {=>y-3=\frac{8}{2}(x+1)} \\\\ {=>y-3=4(x+1)} \\\\ {=>y-3=4 x+4}\end{array}$

Hence equation of line passing through (-1 , 3) and ( 1 , 11 ) is y - 3 = 4x + 4