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3 years ago

11

If n=3 then what is (4n-2) (7-2)

1 answer:

babymother [125]3 years ago

7 0

The value of equation when n = 3 is 50

<em><u>Solution:</u></em>

<em><u>Given equation is:</u></em>

$(4n -2)(7-2)$

We have to find the value of equation when n = 3

By plugging in n = 3 in given equation we can find the value of given equation

<em><u>Substitute n = 3 in given equation</u></em>

$\rightarrow (4(3) -2)(7-2)\\\\Solve\ the\ above\ equation\\\\\rightarrow (12-2)(7-2)\\\\\rightarrow (12 - 2)(5)\\\\Simplify\ the\ above\ equation\\\\\rightarrow 10 \times 5 = 50$

Thus the value of equation when n = 3 is 50

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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

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Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

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