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3 years ago

How to graph exponential function y=6^x-4

1 answer:

7 0

That is an exponential function. It grows all over the range, from - ∞ to + ∞.

The limit when f(x) goes of - ∞ is zero, so y = 0 there is the asymptote to the left side.

The value of f(x) for x = 4 is 1: f(4) = 6 ^ (4 - x) = 6 ^ (4 - 4) = 6^0 = 1. So, the y intercept is y = 0.

The function grows as x goes to infinity.

You can finds some other values of the function to help to sketch the graph.

x f(x) = 6 ^ (x - 4)

-100 6^ ( -104) = 1.18 * 10^ (-81)

- 10 6^ (-14) = 1.28 - 10^ -11

3 6^ (-1) = 1/6 = 0.17

4 6^0 = 1

14 6^ (10) = 60,466,176

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What is (x)=8.00+0.20x

monitta

Answer:

x=10

Step-by-step explanation:

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3 years ago

Read 2 more answers

Dont really understand how to do this

bija089 [108]

Answers:

$t_{10} = -22 \ \text{ and } S_{10} = -85$

========================================================

Explanation:

$t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2$

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

$t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4$

and so on. This process may take a while to reach $t_{10}$

There's a shortcut. The nth term of any arithmetic sequence is

$t_n = t_1+d(n-1)$

We plug in $t_1 = 5 \text{ and } d = -3$ and simplify

$t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8$

Then we can plug in various positive whole numbers for n to find the corresponding $t_n$ value. For example, plug in n = 2

$t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2$

which matches with the second term we found earlier. And,

$tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}$

---------------------

The notation $S_{10}$ refers to the sum of the first ten terms $t_1, t_2, \ldots, t_9, t_{10}$

We could use either the long way or the shortcut above to find all $t_1$ through $t_{10}$ . Then add those values up. Or we can take this shortcut below.

$Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}$

The sum of the first ten terms is -85

-----------------------

As a check for $S_{10}$ , here are the first ten terms:

t1 = 5
t2 = 2
t3 = -1
t4 = -4
t5 = -7
t6 = -10
t7 = -13
t8 = -16
t9 = -19
t10 = -22

Then adding said terms gets us...

5 + 2 + (-1) + (-4) + (-7) + (-10) + (-13) + (-16) + (-19) + (-22) = -85

This confirms that $S_{10} = -85$ is correct.

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2 years ago

Can y’all help me on question six?!

Anna [14]

Answer:

c 2:1

Step-by-step explanation:

8/4=2

4/4=1

8:4 simplified is 2:1

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Answer:

wdym

Step-by-step explanation:

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On the number line below, P represents a number. What is the value of the opposite of that number?

Alex787 [66]

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