we are given
skew lines as
L1: x = 2 + t, y = 2 + 6t, z = 2t
L2: x = 2 + 2s, y = 4 + 14s, z = −1 + 5s
Firstly, we will find directional vector
now, we will find cross product
we are given two points as
P: (2,2,0) and Q:(2,4,-1)
The dot product of orthogonal vectors is zero
now, we can find distance from point Q
..........Answer