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Naddika [18.5K]
4 years ago
11

Anyone really good at right triangles and trigonometry? I need help ASAP.

Mathematics
2 answers:
Verizon [17]4 years ago
5 0
Can help you w/ your problem
9966 [12]4 years ago
3 0
To some extent, "yea".. by d way... Whats your ques?? But dont be completely sure about solving it..
You might be interested in
PLEASE HELP
11111nata11111 [884]

Answer:

1).  The constant of variation is 7

2).  w = 6 for the given values of x and y

Step-by-step explanation:

"Varies jointly" tells us that y is a direct result of a mathematic operation involving x and w.  We will assume y is directly prorportional to x and w, in the sense that we can find a multiplicative relationship of the form y=Kxw, where K is the constant of variation.

We are given one data point:  y=-42 where x is 2 and w is -3.  Let's put those values into our trrial expression:

y=Kxw

-42=K(2)(-3)

-42 = -6K

K = 7

<h2>The expression becames  <u>y = 7xw</u></h2>

The constant of variation is 7.

The value of w for y=3 and x=(1/14) would be:

 

  y=7xw

  3 = 7*(1/14)*w

3 = (1/2)*w

<h2><u>w = 6</u></h2>
7 0
1 year ago
Read 2 more answers
Given that PS is the perpendicular bisector of QR, PQ=3.5m+18, and PR=6m+3, identify PQ.
kolbaska11 [484]

Answer:

PQ=39\ units

Step-by-step explanation:

we know that

QS=RS ----> equation A

Applying Pythagoras Theorem

PQ^2=SP^2+QS^2 -----> equation B

PR^2=SP^2+RS^2-----> equation C

substitute equation A in equation C

PR^2=SP^2+QS^2

we have that

PR^2=PQ^2

so

PR=PQ

substitute the given values

6m+3=3.5m+18

Solve for m

6m-3.5m=18-3

2.5m=15

m=6

Find the value of PQ

PQ=3.5m+18

substitute the value of m

PQ=3.5(6)+18

PQ=39\ units

8 0
4 years ago
Read 2 more answers
Please just answer number 5
miv72 [106K]
The answer is Number 5.
3 0
3 years ago
The length of a rectangle is 33 meters less than twice the width. if the area of the rectangle is 464464 square​ meters, find th
vfiekz [6]
Good night from Canada!
Let W be the width in meters
Let L be the length in meters. 

L*W=464464
L=2W-33
(2W-33)*W=464464
2W^2-33W=464464
2W^2-33W-464464=0
Use the quadratic formula to solve for the zeros 
x=-b√b²-4ac/2a
Sub in b=-33 a=2 and c=-464464 and solve using position and negative values for the √b.
We get:
w=490.225 and w=473.725
Through simple algebra we can figure out that x=490.225 is more accurate when using it with the other equations and solving for the given area. 
L=2*490.225-33
L=947.45
947.45*490.225=464463.7

Therefore the length is 947.45m and the width is 490.225m.

Hope this helps!

8 0
3 years ago
What is the axis of symmetry for f(x) = 2x − 8x + 8? (1 point) Select one: a. x = −2 b. x = −3 c. x = 3 d. x = 2
ExtremeBDS [4]

Answer:

x=2

Step-by-step explanation:

F(x) = 2x^2 - 8x +8

Axis of symmetry lies at the x coordinate of vertex

To find x coordinate of vertex use formula

x=\frac{-b}{2a}

from the given f(x) , a= 2 and b = -8

Plug in all the values

x=\frac{-(-8)}{2(2)}

x=\frac{8}{4}=2

x=2

So the axis of symmetry at x=2

6 0
3 years ago
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