<h3>
Answer: 2 seconds</h3>
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Explanation:
I'll be using x in place of t
The equation given is y = -4.9x^2 + 19.8x + 58
It is of the form y = ax^2 + bx + c which is the standard form for quadratics.
We have,
Plug the first two values into the equation below
h = -b/(2a)
h = -19.8/(2*(-4.9))
h = 2.0204081632653
That value is approximate.
Rounding to the nearest whole number gets us roughly h = 2
Recall that (h,k) is the vertex of the parabola. In this case, it's the highest point. The cannonball reaches the highest point at roughly 2 seconds.
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Extra side notes:
- To find the maximum height, plug the h value into the original equation. This will yield the value of k.
- To find the cannonball's flight time, plug in y = 0 and solve for x. Ignore the negative x solution.
Answer:
Point B is (3, 8)
Step-by-step explanation:
Hello, Jacky,
Note that points A and C have the same x-coordinate and thus lie on the same vertical line, which is x = 3. To determine the length of this directed line segment, we need only subtract 4 from 9, obtaining 5.
Now if we start at (3,4), move up 4 units along this vertical line, plot a point there, and finally move 1 more unit along this line to C(3, 9), we will have partitioned the line in the ratio 4:1. To find the coordinates of this point, we simply take x = 3 (see above) and add 4 to y = 4), obtaining the point (3, 8). This is Point B.
Point B is (3, 8)
Answer:
3y=x+5
Step-by-step explanation:
The slope of the line is (1/3). The equation of the line is y=(1/3)x+5/3 or 3y=x+5
