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Luba_88 [7]
3 years ago
9

  Please help:Merv has two jobs. He earns a salary of $45,000 per year as an accountant and $10.50 per hour at his part-time job

. Merv earned $48,570 last year. Let h represent the number of hours Merv worked at his part-time job. Is the statement True or False?
The total amount Merv made working at his part-time job can be found by dividing: 48,570 10.50 _________ The total amount Merv made working at his part-time job can be found by subtracting 48,570 – 45000 _______ An equation that models how many hours Merv worked at his part-time job is: 3570 = 10.50h ____________ An equation that models how many hours Merv worked at his part-time job is 48,570 = 10.50h ____________ Merv worked about 4626 hours at his part-time job. _______________________ Merv worked exactly 340 hours at his part-time job. ____________________
Mathematics
1 answer:
Schach [20]3 years ago
8 0
True false false true divided 4626÷340=13.605882353
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Step-by-step explanation:

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<u>Figure</u><u> </u><u>:</u><u>-</u>

\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$}   \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}

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\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}

<u>On</u><u> </u><u>using</u><u> </u><u>this</u><u> </u><u>formula</u><u> </u><u>,</u><u> </u>

=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg)  \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}

8 0
3 years ago
Read 2 more answers
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