Answer: Ok, i cant drag the endpoints of the segment, but i can tell you how to do it.
First, we know that h(x) joins the points (1, -5) and (9, 1), then h(x) is a line:
h(x) = s*x + b
First, for a line that goes through the points (x1, y1) and (x2, y2), the slope will be:
s = (y2 -y1)/(x2 - x1)
Then in this case, the slope is:
s = (1 - (-5))/(9 - 1) = 0.75
Then we have
h(x) = 0.75*x + b
now, the value of b can be found as:
h(1) = -5 = 0.75*1 - b
b = - 5 - 0.75 = -5.75.
Then our equation is:
h(x) = 0.75*x - 5.75
Now, i gues you want to find the graph of:
y = h(-x)
Then our new function is:
g(x) = h(-x) = -0.75*x - 5.75.
Now to find the points, we evaluate this function in the same values of x as before.
g(1) = -0.75*1 - 5,75 = -6,5
the point is (1, -6.5)
the second point is when x = 9.
g(9) = -0.75*9 - 5.75 = -12.5
The second point is (9, -12.5)
