5. The line that contains the circumcenter in ΔABC is: <em>line k.</em>
6. The line that contains the orthocenter in ΔABC is: <em>line m.</em>
7. The line that contains the centroid in ΔABC is: <em>line l.</em>
8. The line that contains the centroid in ΔABC is: <em>line n.</em>
<h3>What is the Circumcenter of Triangle?</h3>
Circumcenter is the point where all three perpendicular bisectors of the three sides of a triangle meet and they are of equal distance from the three vertices of the triangle.
- The line that contains the circumcenter in ΔABC is: <em>line k.</em>
<h3>What is the Orthocenter of a Triangle?</h3>
Orthocenter is the point in a triangle where the three altitudes that are perpendicular to the opposite sides and connect with the vertices of the triangle intersect.
- The line that contains the orthocenter in ΔABC is: <em>line m.</em>
<h3>What is the Centroid of a Triangle?</h3>
The centroid of a triangle is a the point of intersection where all three medians of a triangle. Medians of a triangle connects the vertices to the midpoints of the opposite sides of a triangle.
- The line that contains the centroid in ΔABC is: <em>line l.</em>
<h3>What is the Incenter of a Triangle?</h3>
The incenter of a triangle is the point in a triangle where all three angle bisectors of the vertices of a triangle.
- The line that contains the centroid in ΔABC is: <em>line n.</em>
Learn more about centers of a triangle on:
brainly.com/question/16045079
Answer:
y = -7x + 27 is the point slope equation that passes through the two points
Step-by-step explanation:
Here, we want to write the equation of the line between (3,6) and (5,-8)
Mathematically, the equation of the line that passes through both points can be represented by ;
y = mx + c
where m is the slope and c is the y-intercept
Let’s find the slope m first;
Mathematically;
slope m = y2-y1/x2-x1
where (x1,y1) = (3,6) and (x2,y2) = (5,-8)
Substitute these values in the slope equation , we have the following;
m = (-8-6)/(5-3) = -14/2 = -7
So the equation becomes;
y = -7x + c
we still need the value of c
To get this, we can substitute any of the points in the equation, where x is the x coordinate of the point and y is the coordinate of the point.
Let’s use (3,6)
Thus we have;
6 = -7(3) + c
c = 6 + 21
c = 27
So the equation becomes;
y = -7x + 27
(3 + 2i)(5 + i)
15 + 3i + 10i + 2i^2
15 + 13i - 2
13 + 13i
