<h2>RS+ST=RT</h2><h2>RS=RT-ST</h2><h2>RS=4.0-1.6</h2><h2>RS=2.4</h2>
Angles ∡DBE ≅ ∡ACD= 3x reason - angles with parallel arms
Angles ∡ADC and ∡ADB=95° are supplemental angles which means
∡ADC + ∡ADB=180° => ∡ADC = 180° - ∡ADB= 180°-95°= 85°
In the triangle we have ∡ADC + ∡ACD + ∡CAD = 180° =>
85 + 3x + 2x = 180 => 85 + 5x = 180 => 5x= 180-85 => 5x=95
x=95/5 => x=19°
Good luck!!!
Answer:
The food would last 51 days
Step-by-step explanation:
After 15 days are over, you could say that the 16th day would be as follows -
80 soldiers, food finished in 60 - 15 = 45 days.
If 20 more soldiers arrive, there would be a total of 100 soldiers, so if 80 soldiers can finish their food in 45 days - 1 soldier can finish = 45 * 80. Respectively, 100 soldiers can consume their food in ( 45 * 80 ) / 100 = 36 days.
As 15 days are already over, adding 36 more days = 51 days
The food would last 51 days if 20 <em>more</em> soldiers join after 15 days
<u><em>There are several possible ways to answer this question, but I hope that explanation helps!</em></u>
Answer:
B
Step-by-step explanation:
Givens
a = 2 sqrt(3)
b = 3 sqrt(2)
c = ?
Formula
a^2 + b^2 = c^2
Solution
- (2sqrt(3))^2 = 2*2 * sqrt(3)*sqrt(3)
- (2sqrt(3))^2 = 4 * 3
- (2sqrt(3))^2 = 12
- (3sqrt(2))^2 = 3 * 3 * sqrt(2)*sqrt(2)
- (3sqrt(2))^2 = 9 * 2
- (3sqrt(2))^2 = 18
(2sqrt(3)^2 + 3sqrt(2)^2 ) = c^2
4*3 + 9*2 = c^2
12 + 18 = c^2
c^2 = 30
sqrt(c)^2 = sqrt(30)
c = sqrt(30)
Answer
B
