Answer:
The original length was 41 inches and the original width was 16 inches
Step-by-step explanation:
Let
x ----> the original length of the piece of metal
y ----> the original width of the piece of metal
we know that
When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box
The dimensions of the box are

The volume of the box is equal to


so

simplify
-----> equation A
Remember that
The piece of metal is 25 in longer than it is wide
so
----> equation B
substitute equation B in equation A

solve for y

Solve the quadratic equation by graphing
using a graphing tool
The solution is y=16
see the attached figure
Find the value of x

therefore
The original length was 41 inches and the original width was 16 inches
Answer:
the measure of angle x is 48
The value of a is 80
Step-by-step explanation:
The distance of a point
from the y-axis can be written as

because the x-coordinate of the y-axis is zero.
Similarly, the distance of a point
from the x-axis can be written as

Since the y-coordinate of the x-axis is zero.
In this problem:
- The distance of the point A (−30, −45) from the y-axis can be written as

- The distance of point B (a,a) from the x-axis can be written as

Since
.
We are told that 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(a, a), which means

Therefore,

And solving for a,

Learn more about distance:
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9514 1404 393
Answer:
(2/3)(e^t +1)^(3/2)
Step-by-step explanation:
Use the substitution ...
u = e^t +1
Then du = e^t and you are finding the integral of ...
∫u^(1/2)·du
which you know by the power rule is ...
(2/3)u^(3/2) = (2/3)(e^t +1)^(3/2)
27 x 1.25= 33.75
5 x 1.99=9.95
1 x 1.50= 1.50
add that up =45.2
/26 students = 1.73 dollars